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2 years ago

14 + w is the same as which expression?

Mathematics

2 answers:

Leya [2.2K]2 years ago

8 0

Answer:

Step-by-step explanation:

14 + w is the same as w + 14

coldgirl [10]2 years ago

5 0

Answer:

C. w + 14.

Step-by-step explanation:

The order does not matter when you are adding terms.

this is called the Commutative Property of Addition.

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Sedbober [7]

Answer:

60 mins

Step-by-step explanation:

15+45=60

4 0

3 years ago

The tama, Japan,monorail carries 92,700 riders each day. If the monorail usually carries 5,150 per hour how many hours does the

mrs_skeptik [129]

92700/5150 = 18.....so it runs 18 hrs per day

5 0

3 years ago

Read 2 more answers

Help can you answer this? and show working out

Nataly [62]

What number do you need help with

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3 years ago

A bus has 15 passengers. At the first stop, 5 passengers board the bus and 2 passengers get off the bus. At the second stop, 3 p

andrezito [222]

Stop 1 : -

15 + 5 = 20

20 - 2 = 18

So, on the first stop 18 passengers were left on the bus going to the next stop.

Stop 2 : -

18 + 3 = 21

21 - 15 = 6

So, 6 passengers get off at the 2nd stop.

Hope I helped ya!!

8 0

3 years ago

Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

<u>Step-by-step explanation:</u>

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

⇒ $sinx = 2 cos^2 x-1$

⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

Since , $sin(\pi -x)=sinx$

⇒ $x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}$

Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

3 0

3 years ago