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3 years ago

X^2+9x+20=0 What are the steps to solve by factoring?

2 answers:

6 0

First simplify the equation and next multiply the 20 with the x^2 and find a number that adds together to give you the middle

Butoxors [25]3 years ago

6 0

Answer:

x = -5 or x = -4

Step-by-step explanation:

Given equation is :

x²+9x+20 = 0

We have to solve above equation by factoring.

Step 1. Split the middle term of given equation so that the sum of two term should be 9 and their product should be 20.

Terms are 4 and 5.

Their product is 4.5 = 20 and their sum is 4+5 = 9

x²+5x+4x+20 = 0

Step 2. Making two groups and taking common ,we get

x(x+5)+4(x+5) = 0

Step 3. Taking (x+5) as common , we get

(x+5)(x+4) =0

Step 4. Applying Zero-Product Property to above equation ,we get

x+5 = 0 and x+4 = 0

Step 5. Separating x,we get

x = -5 or x = -4 Which is the answer.

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I Need help. Thanks.

PIT_PIT [208]

Answer:

Step-by-step explanation:

$-2(5y-5)-3y\leq -7y+22$

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$-10y+10-3y\leq -7y+22$

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3 years ago

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a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s

slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So, $w = k V$ , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h distance, pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is, $V= \frac{1}{3} *A* 5$

So, weight of original pyramid, $W = k *(\frac{1}{3} *A* 5) = 800$

Volume of small pyramid is, $v = \frac{1}{3}* a* h$

So, weight of small pyramid, $w = k*(\frac{1}{3}* a* h)=400$

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So, $\frac{a}{A} = (\frac{h}{5}) ^{2}$

$a = (\frac{h}{5} )^{2}A$

Substituting value of a in equation $k*(\frac{1}{3}* a* h)=400$

So, $k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400$

$(k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400$

Since, $(k *\frac{1}{3} *A* 5) = 800$ , substitute in above equation.

So, $800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet$

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2 years ago

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