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3 years ago

Help me thank youuuuu

Mathematics

1 answer:

torisob [31]3 years ago

6 0

Answer:

Its negative

Step-by-step explanation:

All you are doing with this problem is subtracting 39 from 2364.

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What is the image point of (-1,1) after a translation left 2 units and down 2 units?

AveGali [126]

Answer:

The new point is (-3,-1)

Step-by-step explanation:

yessir

3 0

3 years ago

Cities A & B are 5 inches apart on a map. Cities Ce Dare 4 inches apart. If C & D are 900 miles apart how many miles apa

Afina-wow [57]

Answer:

Cities A and B are 1,125 miles apart

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Distance between A and B in the map = 5 inches

Distance between C and D in the map = 4 inches

Real distance between C and D = 900 miles

2. How many miles apart are cities A and B?

We will solve the question, using Direct Rule of Three, as follows:

Distance in the map Real distance

A - B 5 inches x

C - D 4 inches 900 miles

***************************************************

4x = 900 * 5

4x = 4,500

x = 4,500/4

x = 1,125 miles

Cities A and B are 1,125 miles apart

Same answer to question 14701120, answered by me today

8 0

4 years ago

Name the edges of an hexagonal pyramid

aleksandrvk [35]

Given:

Hexagonal pyramid

To find:

The edges of an hexagonal pyramid.

Solution:

Edges means lines which connecting to vertices.

Edges in the base of the pyramid:

AB, BC, CD, DE, EF, FA

Edges in the triangular shape of the pyramid:

AG, BG, CG, DG, EG, FG

Therefore edges of an hexagonal pyramid are:

AB, BC, CD, DE, EF, FA, AG, BG, CG, DG, EG, FG

4 0

4 years ago

A cafe stores ice cream in a large hemisphere-shaped bowl with a diameter of 36 cm.

skelet666 [1.2K]

Answer:

1115.8

Step-by-step explanation:

3 0

3 years ago

Need help find volume of this

zhenek [66]

let's notice that this triangular pyramid has a triangular base, that triangle has a base of 14 and an altitude of 8.485, whilst the pyramid also has a height of 12.

$\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=&area~of\\ &its~base\\ h=&height\\ \cline{1-2} h=&12\\ B=&\frac{1}{2}(14)(8.485) \end{cases}\implies V=\cfrac{1}{3}\left[ \cfrac{1}{2}(14)(8.485) \right](12) \\\\\\ V=4\cdot (7\cdot 8.485)\implies V=237.58$

8 0

3 years ago