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Bas_tet [7]
4 years ago
12

Name the edges of an hexagonal pyramid​

Mathematics
1 answer:
aleksandrvk [35]4 years ago
4 0

Given:

Hexagonal pyramid

To find:

The edges of an hexagonal pyramid.

Solution:

Edges means lines which connecting to vertices.

Edges in the base of the pyramid:

AB, BC, CD, DE, EF, FA

Edges in the triangular shape of the pyramid:

AG, BG, CG, DG, EG, FG

Therefore edges of an hexagonal pyramid are:

AB, BC, CD, DE, EF, FA, AG, BG, CG, DG, EG, FG

You might be interested in
A tortoise is walking in the desert. It walks for 4.8 meters at a speed of 3 meters per minute. For how many minutes does it wal
kirill [66]
It is normally smart to write out a diagram of some sort to help you visualize the situation. I made one for this situation, although it might now suit you as well as it would me. 

The idea behind this problem is to make you understand rates. Rates being the same thing as a slope. If you have learned about that already then that will help a lot, but if you haven't then that's fine. 

So we have 4.8m and we traveled at a speed of 3 meters per 1 minute. A rate you are probably pretty familiar with is mph. Which is Miles per Hour. Or if you don't live in the U.S. Kmph. Which is Kilometers per Hour. 

What you do to solve these type of problems is you take the given value and you use the rate to get the value you want.

The easiest way to do this is to make sure the signs (Meters) "cancel" out.  

4.8m * (1min / 3m) 

To cancel something out you need to have it over itself. Here are a few examples: 

3/3 = 1
4/4 = 1 
100,000/100,000 = 1
598/598 = 1

In the case of units, such as meters. They go *poof* from the problem. 
So we have this problem: 
(4.8m*1 minute) / 3m = ? minutes

4.8/3 = 1.6


If you want the answer in fractional form... here is how you do it: (I won't explain it because you most likely won't need to do this, but if you want to know how to do it then just ask)

4(8/10) 
4(4/5)
(24/5)/3 
(24/5) * (1/3) 

24/15
8/5 is our final fractional answer!

5 0
4 years ago
How do you solve this problem?
jekas [21]
Very nice problem. You should look up the history of this question. It has a very long one having to do with mirrors made between 50 BC and 50 AD.

Step One
Find AB, BC, AC
Before beginning this problem, I'm going to arbitrarily name 
c = AB
a = BC
b = AC It just makes the calculations easier.

AB = radius of the large circle - radius of the medium circle = 20.62 - 8.04 = 12.58
BC = Radii of the two smaller circles added together = 8.04 + 7.35 = 15.39
AC = Radius of the large circle - Radius of the small circle = 20.62 - 7.35 = 13.27

So
a = 15.39
b = 13.27
c = 12.58

Step Two
Find Angle A or <BAC
a^2 = b^2 + c^2 - 2*b*c * Cos(A)
15.39^2 = 12.58^2 + 13.27^2 - 2 * 12.58 * 13.27 * Cos(A)
236.852 = 158.26 + 176.1 -  333.87 * Cos(A)
236.852 = 334.4 - 333.87*Cos(A)
-97.55 = - 333.87 *  Cos(A) 
-97.55 / -333.87 = Cos(A)
0.2922 = cos(A)
A = cos-1(0.2922)
A = 73.01 degrees

Step Three
Just to see if you understand what was done, I'll give you the givens for finding c, and the answer and you can work through the calculations to see if your answer agrees with mine. If it doesn't PM me.
c = 12.58
b = 13.27
a = 15.39

12.58^2 = 13.27^2 + 15.39^2 - 2*13.27*15.39*Cos(C)
C = 51.42

Step Four
Find <B
Every triangle has 180 degrees so
B = 180 - <A - C
B = 180 - 51.42 - 74.01
B = <54.57. 
I have found a moderator who opened the question up so that I can show you why the Cos law is the only way to do this. If the circles are very disproportionate as in this diagram, then no simple assumption can be made. The cos law is all that will work. I would have posted this earlier, but I didn't think anyone would find another method. It's ingenious but not possible for the situation below.

3 0
3 years ago
Are the following figures similar?
aalyn [17]

a no the corresponding angles are not congruent

∠A ≠ ∠E and ∠D ≠ ∠H


8 0
4 years ago
Read 2 more answers
Solve for x: x^2+4x-5=16x
BigorU [14]
Solve for x: x^2+4x-5=16x
first take 16x from both sides of the equation
x²-12x-5=0
now we have a quadratic. we can solve it by using the quadratic formula
x=-b plus or minus the square root of b²-4ac all divided by 2a
where a=1, b=-12 and c=-5
plug these numbers into the formula
x=12 plus or minus the square root of 144-4x1x-5 all divided by 2
<span>x=12 plus or minus the square root of 164 all divided by 2
or in decimal form </span>x = {12.403124237, -0.403124237}
6 0
3 years ago
Read 2 more answers
Solve the system of equations. y = 2x y = x 2 – 15
inn [45]

Answer:

D. (–3, –6) and (5, 10)

Step-by-step explanation:

The system has equations:

y=2x...(1)

and

y=x^2-15...(2)

Equate both equations;

x^2-15=2x

Rewrite in standard form:

x^2-2x-15=0

We factor to obtain:

(x+3)(x-5)=0

By the zero product principle;

(x+3)=0,(x-5)=0

\implies x=-3,x=5

When x=-3, y=2(-3)=-6

This yields the ordered pair (-3,-6).

When x=5, y=2(5)=10

This yields the ordered pair (5,10).

The correct choice is D.

8 0
3 years ago
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