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3 years ago

Expand. Your answer should be a polynomial in standard form. (x – 4)(x + 7) =

Mathematics

2 answers:

aev [14]3 years ago

3 0

x^2 + 3x - 28

there u go

Ratling [72]3 years ago

3 0

The answer is x^2 + 3x - 28.

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What is 7 4/5 + 8 8/9

Paladinen [302]

7 4/5 = 7 36/45
8 8/9 = 8 40/45
+----------
15 75/45
15 75/45 = 16 30/45

7 0

3 years ago

find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B

SashulF [63]

Answer:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

$a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

$|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3$

$|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5$

And finally we can calculate the angle between the vectors like this:

$cos \theta = \frac{ab}{|a| |b|}$

And the angle is given by:

$\theta = cos^{-1} (\frac{ab}{|a| |b|})$

If we replace we got:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

3 0

3 years ago

Are the triangles similar? Justify your answer

cluponka [151]

Answer:

Yes

Step-by-step explanation:

If you divide all the sides of the larger triangle by 3, it's equivalent to the sides of the smaller triangle. Therefore, they are similar.

4 0

3 years ago

Find the domain of the function:

makkiz [27]

Answer: OPTION C.

Step-by-step explanation:

1. The domain of the function given in the problem are all those values for which the function that is in the denomiantor is different from zero, because the division by 0 is not allowed.

2. You can make the denominator equal to zero and solve it, as you can see below:

$x^{3}-2x^{2}+x=0\\x(x^{2}-2x+1)=0\\x(x-1)(x-1)=0\\x=0\\x=1$