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olganol [36]
3 years ago
11

Geologists recorded the duration (in seconds) of over 500 recent eruptions of the Old Faithful geyser in

Mathematics
1 answer:
Gre4nikov [31]3 years ago
5 0

Answer: C (A unimodal histogram, and the dotted line lands at 210)

Step-by-step explanation:

Khan Academy - “The sample size is reasonably large (n = 30 _> 30), so the sampling distribution of x will be approximately normal even though the population isn’t.”

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The O'Niell family decided to book a hotel for a trip to Orlando, FL from Saturday 6/3 through Friday 6/9. They decide to stay a
Citrus2011 [14]
Six nights.

1. Saturday night
2. Sunday night
3. Monday night
4. Tuesday night
5. Wednesday night
6. Thursday night
8 0
2 years ago
Solve by completing the square and show steps <br> x^(2)+6x+5=0
Crazy boy [7]
X ^2 +6x+ 5
(x+2)(x+3)

2 + 3 = 5
While also 2•3= 6
The two numbers have to equal b when multiplied and c when added
4 0
3 years ago
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
2. Simplify the expression x^2+x-28/x^2-7x+12
tankabanditka [31]
The answer is   x^4-6x^3+12x^2-28/x^2


5 0
3 years ago
Solve for x.<br> 8(x + 1) - 3(x + 4) = 7(2 - x)<br> Ox=11<br> Ox=-11<br> Ox= -1 1 /<br> Ox=11/
inna [77]

Answer:

1.5

Step-by-step explanation:

8(x + 1) - 3(x + 4) = 7(2 - x) \\ 8 x + 8 - 3x - 12 = 14 - 7x \\ 8x - 3x + 7x = 14 - 8 + 12 \\ 12x = 18 \\ x =  \frac{18}{12} \\ x =  \frac{3}{2}  \\  x = 1.5

3 0
3 years ago
Read 2 more answers
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