Answer:
about 1099 pounds
Step-by-step explanation:
The weight of the truck is directed downward. It is countered by a force normal to the plane of the hill and one that is parallel to the plane of the hill. The question is asking about this latter force.
The magnitude of the force parallel to the hillside required to keep the truck stationary is ...
(2600 lb)·sin(25°) ≈ 1098.81 lb ≈ 1099 lb
3260/2 = 1630
160/2 = 80
Loser received 1630 - 80 = 1550 votes.
Winner received 1630 + 80 = 1710 votes.
Answer:
Step-by-step explanation:
(a) You use the fact that the lengths RS and ST total the length RT.
RS +ST = RT
(6y+3) +(3y+5) = 80 . . . . . substitute the given values
9y +8 = 80 . . . . . . . . . . . . .simplify
9y = 72 . . . . . . . . . . . . . . . .subtract 8
72/9 = y = 8 . . . . . . . . . . . .divide by the coefficient of y
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(b) Now, the value of y can be substituted into the expressions for RS and ST to find their lengths.
RS = 6y +3 = 6·8 +3
RS = 51
ST = 3y +5 = 3·8 +5
ST = 29
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<em>Check</em>
RS +ST = 51 +29 = 80 = RT . . . . the numbers check OK
Answer:
The average rate of change for the given function in the interval (-5, -1) is 0 (zero)
Step-by-step explanation:
The average rate of change of a function over an interval is the quotient between the difference between the function evaluated at the ends of the interval divided by the length of the interval. That is for our case:
the average rte of change of h(t) in the interval (-5, -1) is:
so we find:
then the average rate of change becomes:
Answer:
what class do you have because i have finished all required mathematics
Step-by-step explanation:
