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3 years ago

12

The radius of Mars is 3397 km; and its mass is 6.42x10²³ kg. What is the acceleration due to gravity at an altitude of 485 km ab

ove the surface of Mars?

2 answers:

Gekata [30.6K]3 years ago

4 0

Answer:nfeergnjknrtgrth

Explanation:

Gwar [14]3 years ago

4 0

Answer:

F = GMm/r^2

MA = GMm/r^2

A = GM/r^2

A = (6.67 * 10^-11)(6.42 * 10^23) / (3.37 * 10^6)^2

A = 3.77 m/s^2

Explanation:

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mr Goodwill [35]

The magnetic force between two wires is 0.052 N which is attract each other.

We need to know about magnetic force on a current-carrying wire formula to solve this problem. The magnetic force on two wires with same direction of current is

F = μ₀ . I1 . I2 . L / ( 2π . r )

where μ₀ is vacuum permeability (4π×10‾⁷ H/m) F is the magnetic force, I is current, L is the length of wire, r is distance of 2 wires.

From the question above, we know that:

L = 25 m

r = 6 cm

I1 = I2 = 25 A

By substituting the parameter, we get

F = μ₀ . I1 . I2 . L / ( 2π . r )

F = 4π×10‾⁷ . 25 . 25 . 25 / (2π . 0.06)

F = 0.052 N

Hence, the force between two wires is 0.052 N which is attract each other.

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2 years ago

A worker kicks a flat object lying on a roof. The object slides up the incline 10.0 m to the apex of the roof, and flies off the

11111nata11111 [884]

Answer:15.20 m

Explanation:

Given

initial velocity $(v_i)=15 m/s$

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inclination $\theta =43.5^{\circ}$

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$a_{net}=\mu _kg\cos \theta +g\sin \theta$

$a_{net}=0.435\times 9.8\times \cos 43.5+9.8\times \sin 43.5$

$a_{net}=3.09+6.74=9.83 m/s^2$

$v^2-u^2=2as$

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So Particle launches with a speed of 5.31 m/s at an angle of \theta $=43.5$

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$h_{max}=\frac{(5.31)^2\sin ^2(43.5)}{2\times 9.81}$

$h_{max}=0.679$

Total height raised is $0.679+\frac{10}{\sin 43.5} =15.20 m$

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3 years ago

A DC motor's magnet has a magnetic field that ____ the wire loop's magnetic field, therefore causing the loop to rotate.

jek_recluse [69]

b. deflects. A DC motor's magnet has a magnetic field that <em><u>deflects</u></em> the wire loop's magnetic field, therefore causing the loop to rotate.

When a conductor, through which an electric current passes, is immersed in a magnetic field, it experiences a deflects force according to the Law of Lorentz creating as result that the loop rotate.

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3 years ago

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3 years ago

A motorboat traveling from one shore to the other at a rate of 5m/s east encounters a current flowing at a rate of 3.5m/s north

nikdorinn [45]

Answer:

Resultant velocity will be equal to 6.10 m/sec

Explanation:

We have given a motorbike is traveling with 5 m/sec in east

And a current is flowing at a rate of 3.5 m /sec in north

We know that east and north is perpendicular to each other

So resultant velocity will be vector sum of both velocity

So resultant velocity $v=\sqrt{5^2+3.5^2}=6.10m/sec$

So resultant velocity will be equal to 6.10 m/sec

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4 years ago