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Fittoniya [83]
3 years ago
12

The radius of Mars is 3397 km; and its mass is 6.42x10²³ kg. What is the acceleration due to gravity at an altitude of 485 km ab

ove the surface of Mars?
Physics
2 answers:
Gekata [30.6K]3 years ago
4 0

Answer:nfeergnjknrtgrth

Explanation:

Gwar [14]3 years ago
4 0

Answer:

F = GMm/r^2

MA = GMm/r^2

A = GM/r^2

A = (6.67 * 10^-11)(6.42 * 10^23) / (3.37 * 10^6)^2

A = 3.77 m/s^2

Explanation:

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Answer:

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You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks t
Sladkaya [172]

Answer:

0.767

Explanation:

The work done on the truck by the frictional drag force is given by

W=-Fd

where

F is the magnitude of the frictional force

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The negative sign is due to the fact that the force of friction is opposite to the motion of the truck

The force of friction can also be written as:

F=\mu mg

where

\mu is the coefficient of kinetic friction between the truck and the lane

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g is the acceleration of gravity

So we can rewrite the work done as

W=-\mu mg d (1)

According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the truck:

W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2 (2)

where

v = 0 is the final velocity of the truck

u = 23.9 m/s is the initial velocity of the truck

By combining (1) and (2) we get

-\frac{1}{2}mu^2 = -\mu mg d

And solving for \mu, we find the minimum coefficient of kinetic friction able to stop the truck in a distance d:

\mu = \frac{u^2}{2gd}=\frac{23.9^2}{2(9.8)(38.0)}=0.767

7 0
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Then, the taped pole of the third magnet has to be equal to one of the first two taped poles and opposite to the other of the first two taped poles.

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