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Alecsey [184]
3 years ago
11

A wattage rating of a lightbulb is the power it consumers when it is connected across a 120 V potential difference. How does the

resistance of a 60 W light bulb compare to that of a 100 W light bulb?
A. The 100 W bulb has the same resistance
B. The 100 W bulb has more resistance
C. The 100 W bulb has less resistance
Physics
1 answer:
navik [9.2K]3 years ago
7 0

Answer:

The answer is C.

120 V with 60 W light bulb is 240 ohms.

120 V with 100 W light bulb is 144 ohms.

The 100 W bulb has less resistance :)

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Approximately how many kelvins are equal to 60°f? <br> a. 333 <br> b. 323 <br> c. 413 <br> d. 289
Afina-wow [57]
D. 289
Take the formula:
K=5/9(Fahrenheit-32)+273
Plug in Fahrenheit
K=5/9 (60-32)+273
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3 0
3 years ago
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Two particles each have the same mass but particle #1 has four times the charge of particle #2. Particle #1 is accelerated from
marin [14]

Answer:

 v_2 = 2*v  

Explanation:

Given:

- Mass of both charges = m

- Charge 1 = Q_1

- Speed of particle 1 = v

- Charge 2 = 4*Q_1

- Potential difference p.d = 10 V

Find:

What speed does particle #2 attain?

Solution:

- The force on a charged particle in an electric field is given by:

                                       F = Q*V / r

Where, r is the distance from one end to another.

- The Net force acting on a charge accelerates it according to the Newton's second equation of motion:

                                      F_net = m*a

- Equate the two expressions:

                                      a = Q*V / m*r

- The speed of the particle in an electric field is given by third kinetic equation of motion.

                                      v_f^2 - v_i^2 = 2*a*r

Where, v_f is the final velocity,

            v_i is the initial velocity = 0

                                      v_f^2 - 0 = 2*a*r

Substitute the expression for acceleration in equation of motion:

                                       v_f^2 = 2*(Q*V / m*r)*r

                                       v_f^2 = 2*Q*V / m

                                       v_f = sqrt (2*Q*V / m)

- The velocity of first particle is v:

                                       v = sqrt (20*Q / m)

- The velocity of second particle Q = 4Q

                                       v_2 = sqrt (20*4*Q / m)

                                       v_2 = 2*sqrt (20*Q / m)

                                       v_2 = 2*v  

3 0
3 years ago
Sally goes on a hike. The distance she walks compared to the amount of time she walks is shown on the graph. Which statement is
Neko [114]
According to the task there should be the graph that supports Sally's hike, but after looking on the options it seems that Sally doesn't walks at a constant rate and there is the negative option that coincides with my thoughts. So, I bet the false statement is the third option represented in the scale above.
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3 years ago
All electric devices are required to have identifying plates that specify their electrical characteristics. The plate on a certa
masha68 [24]

Answer:

R= 20 ohm  

Explanation:

Given that

Current ,I = 6 A

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Lets take resistance of the stem iron = R

We know that ,the relationship between current ,voltage difference and resistance is given as

ΔV = I R

R=\dfrac{\Delta V}{I}

Now by putting the values in the above equation we get

R=\dfrac{120}{6}\ ohm

R= 20 ohm

Therefore the resistance of the steam  will be 20 ohm.

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