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Anarel [89]
3 years ago
13

A ladder 7.85 m long leans against the side of a building. If the ladder is inclined at an angle of 79.5° to the horizontal, wha

t is the horizontal distance from the bottom of the ladder to the building?
Physics
1 answer:
Slav-nsk [51]3 years ago
5 0

Jsdjdjjjdjdjd

Explanation:Sjsjsjsmjsjddhdmddjdidujddjdujddmjsisisi daddy dickkkdududjdjsjsusjsususuksuckmpormmjsjdjsjxjxxjjjsusjhs

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Two identical conducting spheres, A and B, carry equal charge. They are stationary and are separated by a distance much larger t
podryga [215]

Answer:

8F_i = 3F_f

Explanation:

When two identical spheres are touched to each other, they equally share the total charge. Therefore, When neutral C is first touch to A, they share the initial charge of A equally.

Let us denote that the initial charge of A and B are Q. Then after C is touched to A, their respective charges are Q/2.

Then, C is touched to B, and they share the total charge of Q + Q/2 = 3Q/2. Their respective charges afterwards is 3Q/4 each.

The electrostatic force, Fi, in the initial configuration can be calculated as follows.

F_i = \frac{1}{4\pi\epsilon_0}\frac{q_Aq_B}{r^2} = \frac{1}{4\pi\epsilon_0}\frac{Q^2}{r^2}[/tex}The electrostatic force, Ff, in the final configuration is [tex]F_f = \frac{1}{4\pi\epsilon_0}\frac{q_Aq_B}{r^2} = \frac{1}{4\pi\epsilon_0}\frac{3Q^2/8}{r^2}[/tex}Therefore, the relation between Fi and Ff is as follows[tex]F_i = F_f\frac{3}{8}\\8F_i = 3F_f

7 0
3 years ago
The part of the atom that carries no electric charge
AlexFokin [52]
The answer is: A Neutron
7 0
3 years ago
Define uniform and non uniform
cricket20 [7]

Answer:

When a body moves along a straight line with uniform speed or steady speed is called Uniform motion. When a body moves along a straight line but with variable or change in speed is called non-uniform motion.Hope this answer helps.

7 0
3 years ago
Read 2 more answers
__ is the apparent in the position of an object when viewed from two locations
Yakvenalex [24]
The apparent shift <span>is the apparent in the position of an object when viewed from two locations.

Hope this helps :)</span>
3 0
3 years ago
As a stands, her entire weight is momentarily placed on the heels of her high-heeled shoes. Calculate the pressure exerted on th
Lena [83]

Answer:

Pressure will be 6072449.952Pa

Explanation:

We have given mass of the women m = 65 kg

Radius of the heels r = 0.578 cm = 0.00578 m

We have to find the pressure

We know that pressure is given by

P=\frac{F}{A}=\frac{mg}{A}

So force F = mg = 65×9.8 = 637 N

Area A=\pi r^2=3.14\times 0.00578^2=1.049\times 10^{-4}m^2

So pressure p=\frac{637}{1.049\times 10^{-4}}=6072449.952Pa

5 0
3 years ago
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