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guapka [62]
3 years ago
10

10.Which of the following values does not satisfy the inequality ?

Mathematics
1 answer:
kupik [55]3 years ago
7 0

Answer:

The answer is -4

Step-by-step explanation:

-2x-6<=1

-2(-4)-6<=1

8-6<=1

2<=1 which is False

-2x-6<=1

-2(-3)-6<=1

6-6<=1

0<=1 which is True

-2x-6<=1

-2(-2)-6<=1

4-6<=1

-2<=1 which is True

-2x-6<=1

-2(-1)-6<=1

2-6<=1

-4<=1 which is True

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Which statement is true about polynomial 5s^6t^2 + 6st^9 - 8s^6t^2 - 6t^7 after it has been fully simplified?
Marina86 [1]

Answer:  3t²(2st⁷ - s⁶ - 2t⁵)

<u>Step-by-step explanation:</u>

5s⁶t² + 6st⁹ - 8s⁶t² - 6t⁷     <em>5s⁶t² and - 8s⁶t² are like terms which = -3s⁶t² when combined</em>

=          6st⁹ - 3s⁶t² - 6t⁷      <em>next, factor out the GCF of 3t²</em>

=      3t²(2st⁷ - s⁶ - 2t⁵)

5 0
4 years ago
Read 2 more answers
Ordered pairs that satisfy y=x^2+1
-BARSIC- [3]
Using an ordered pair is a way of graphing a linear equation on a coordinate plane.
{(-1, 2), (0, 1), (1, 2), (4, 5)}.
5 0
3 years ago
Given the function f(x)=x^2+2x+1, find each value of the function
Paha777 [63]

Answer:

1 9/16

Step-by-step explanation:

F(1/4) means u plug in 1/4 for x

so the equation would be

f(1/4)=1/4^2+2 1/4 + 1

f(1/4)=1/16+1/2+1

f(1/4)= 9/16 +1

f(1/4)= 1 9/16

its not nine teen its one and 9 over 16 just clarification

5 0
3 years ago
How would the factor pairs change if nancy had only 5 posters to arrange?
Romashka [77]

Answer:

Part A) Nancy can arrange the posters in 4 ways

Part B) Nancy can arrange the posters in 2 ways

Step-by-step explanation:

<u><em>The complete question is</em></u>

Nancy has 10 movie posters. She wants to hang them on a wall in equals rows.

A) Find all the ways that she can arrange the posters.

B) How would the factor pairs change if Nancy had only 5 posters to arrange?

Part A) Find all the ways that she can arrange the posters.

we know that

The factors of 10 are

1x10 -----> 1 row of 10 posters

2x5 -----> 2 rows of 5 posters

5x2 -----> 5 rows of 2 posters

10x1 -----> 10 rows of 1 poster

therefore

Nancy can arrange the posters in 4 ways

Part B) How would the factor pairs change if Nancy had only 5 posters to arrange?

we know that

if Nancy had only 5 posters to arrange

then

The factors of 5 are

1x5 -----> 1 row of 5 posters

5x1 -----> 5 rows of 1 poster

therefore

Nancy can arrange the posters in 2 ways

3 0
3 years ago
Find the value of x to the nearest tenth.<br> 9.0<br> 8.6<br> 26.3<br> 5.7
Ket [755]

Answer: x = 9.0

Step-by-step explanation:

From the given right angle triangle,

the hypotenuse of the right angle triangle is x

With m∠39 as the reference angle,

the adjacent side of the right angle triangle is 7

The unknown side represents the opposite side of the right angle triangle.

To determine x, we would apply

the cosine trigonometric ratio which is expressed as

Cos θ = adjacent side/hypotenuse. Therefore,

Cos 39 = 7/x

x = 7/cos 39 = 7/0.777

x = 9.0 to the nearest tenth

5 0
3 years ago
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