Your answer would chlorine. I hope I helped you!
Answer:
0.1127 grams of Mg is used to produce one gram of silver
Explanation:
Write a balanced equation
Mg(s) +2Ag + (aq) --> (aq) + 2Ag(s)
The atomic mass of magnesium is 24.31 g/mol and the atomic mass of silver is 107.84g/mol
1 g Ag of silver is produced from [(1 mol Mg)(24.31 g/mol)] /[ (2mol Ag)(107.84g/mol)]
1 g Ag of silver is produced from 0.1127 grams of Mg
0.1127 grams of Mg is used to produce one gram of silver
Answer:
by playing with each other
Explanation:
the play fight and stuff so when the get older the hunt and stuff yk
Not sure if this is the right place to be looking bud
Answer: A. 4 unpaired electrons
B. Zero unpaired electrons
C. 1 unpaired electron
D. 5 unpaired electrons
E. Zero unpaired electrons
Explanation:
In A, Oxidation state of Co is +3 and Electronic configuration is [Ar]3d6
F is weak field ligand, causes no pairing of Electrons hence it has 4 unpaired electrons&2 are paired in t2g orbitals (dXY)
In B , Mn is in +3 with electronic configuration 3d4&CN is a strong field ligand hence causes pairing of Electrons hence it results 0 unpaired electron
In C, Mn is in +2 with electronic configuration 3d5 sinceCN is a strong field ligand hence it leaves one unpaired electron
In D, Mn is in+2 with 3d5& five unpaired electrons since cl is a weak field ligand causes no pairing.
In E, Rh is in +3, with d6 configuration and it is a low spin complex hence pairing of Electrons involved. So it leaves zero unpaired electrons.