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Mrrafil [7]
3 years ago
5

How many moles of water are present in 55.1 g of H2O

Chemistry
1 answer:
Rashid [163]3 years ago
7 0

Answer:

3.0585147719047385 is the answer

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5. 16.3 g of NaCl is dissolved in water to make 1.75 L of solution. What is the molarity of this solution? A 0.159 M B 0.278 M C
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Answer: The molarity of this solution is 0.159 M.

Explanation:

Given: Mass of solute = 16.3 g

Volume = 1.75 L

Number of moles is defined as the mass of substance divided by its molar mass.

Hence, moles of NaCl (molar mass = 58.44 g/mol) ar calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{16.3 g}{58.44 g/mol}\\= 0.278 mol

Molarity is the number of moles of a substance present in a liter of solution.

So, molarity of the given solution is calculated as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.278 mol}{1.75}\\= 0.159 M

Thus, we can conclude that the molarity of this solution is 0.159 M.

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3 years ago
Select the correct answer. What is the enthalpy for the reaction represented in the following energy diagram? A. +200 kJ B. +350
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Answer:

Option C. +150KJ

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Heat of reactant (Hr) = 200KJ

Heat of product (Hp) = 350KJ

Change in enthalphy (ΔH) =..?

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Change in enthalphy (ΔH) = Heat of reactant (Hp) – Heat of reactant (Hr)

ΔH = Hp – Hr

ΔH = 350 – 200

ΔH = +150KJ

Therefore, the enthalphy for the reaction above is +150KJ

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