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masha68 [24]
2 years ago
15

How many moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas?

Chemistry
1 answer:
tino4ka555 [31]2 years ago
6 0

Taking into account the reaction stoichiometry, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CO₂ + 4 H₄  → CH₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CO₂: 1 mole
  • H₄: 4 moles  
  • CH₄: 1 mole
  • H₂O: 2 moles

<h3>Moles of CH₄ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?

moles of CH_{4} =\frac{85.1 moles of CO_{2}x4 moles of CH_{4} }{1 moles of CO_{2}}

<u><em>moles of CH₄= 340.4 moles</em></u>

Then, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

#SPJ1

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If the ratio of the length of a rectangle to its width is 3 to 2, what is the
borishaifa [10]

Answer:

Length of a rectangle whose width is 4 inches is

<u>6 inches</u>

Explanation:

Ratio of length  to its width is 3 to 2

Let length  = L

Let Width  = B

L: B = 3 : 2 (given)

\frac{L}{B} =\frac{3}{2}

Width ,B = 4

Insert  B in above equation

\frac{L}{B} =\frac{3}{2}

\frac{L}{4} =\frac{3}{2}

cross multiply,

L = \frac{3}{2}\times4

L = 6 inches

Conversion(if required) ,

1 inch = 2.54 cm

6 inch = 2.54 (6)

L = 15.24 cm

8 0
3 years ago
A drop of liquid tends to have a spherical shape due to the property of 1. viscosity. 2. capillary action. 3. surface tension. 4
posledela

Answer:

surface tension.

Explanation:

3 0
4 years ago
6.75 L of carbon dioxide gas are stored at a pressure of 175 atm. If the temperature and number of gas particles do not change,
I am Lyosha [343]

Answer:

4.24 L

Explanation:

  • 6.75 L - 175 atm

x. - 110 atm

  • <u>175atm </u><u>x</u>=<u>742.5L /atm</u>

175atm 175atm

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3 0
3 years ago
In the Haber process for ammonia synthesis, K " 0.036 for N 2 (g) ! 3 H 2 (g) ∆ 2 NH 3 (g) at 500. K. If a 2.0-L reactor is char
lisabon 2012 [21]

Answer : The partial pressure of N_2,H_2\text{ and }NH_3 at equilibrium are, 1.133, 2.009, 0.574 bar respectively. The total pressure at equilibrium is, 3.716 bar

Solution :  Given,

Initial pressure of N_2 = 1.42 bar

Initial pressure of H_2 = 2.87 bar

K_p = 0.036

The given equilibrium reaction is,

                              N_2(g)+H_2(g)\rightleftharpoons 2NH_3(g)

Initially                   1.42      2.87             0

At equilibrium    (1.42-x)  (2.87-3x)     2x

The expression of K_p will be,

K_p=\frac{(p_{NH_3})^2}{(p_{N_2})(p_{H_2})^3}

Now put all the values of partial pressure, we get

0.036=\frac{(2x)^2}{(1.42-x)\times (2.87-3x)^3}

By solving the term x, we get

x=0.287\text{ and }3.889

From the values of 'x' we conclude that, x = 3.889 can not more than initial partial pressures. So, the value of 'x' which is equal to 3.889 is not consider.

Thus, the partial pressure of NH_3 at equilibrium = 2x = 2 × 0.287 = 0.574 bar

The partial pressure of N_2 at equilibrium = (1.42-x) = (1.42-0.287) = 1.133 bar

The partial pressure of H_2 at equilibrium = (2.87-3x) = [2.87-3(0.287)] = 2.009 bar

The total pressure at equilibrium = Partial pressure of N_2 + Partial pressure of H_2 + Partial pressure of NH_3

The total pressure at equilibrium = 1.133 + 2.009 + 0.574 = 3.716 bar

6 0
3 years ago
What happens to the electrons in an ionic bond
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Answer:

Result of the formation of positive and negative ions.

3 0
3 years ago
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