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Leona [35]
2 years ago
11

The radius of a circle is 9 square inches. What is the Area of the Circle? Round your answer to the nearest hundredth. A 56.52 B

254.34 C 28.26 D 14.13 PLZ help me
Mathematics
1 answer:
kondaur [170]2 years ago
7 0

Answer:

hi

Step-by-step explanation:

Find the area of the circles: 1. f. Answer: 379.94 square inches 2. ... Given the radius or diameter, find the circumference AND area of each circle to the nearest tenth. 5. r=9 m. C=56.52 m. A=254.34 square meters ... Round your answer to the nearest tenth. 50.2 square feet 9. A company is manufacturing aluminum lids.

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kenny6666 [7]

Answer:

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E. 3x(2x+3)

I hope this helps

4 0
2 years ago
Explain Well please.
Art [367]
The answer is C,
as she uses SSS to prove its congruent, she uses sides instead of angles so option a and d is not correct. as it needs to prove triangle pqr is congruent to triangle sqr, its not necessary to prove PQ is equal to QR. so the answer is c
7 0
3 years ago
Find the value of <br> (16/81)^3/4
AlexFokin [52]

Answer:

1.92636657×10^-3

Step-by-step explanation:

This question looks quite awful coz it might be (16+81)^3/4 rather than being (16/81)^3/4....But, if it is (16/81)^3/4 the answer is 1.92636657×10^-3

hope you find it helpful....Thanks very much...

5 0
3 years ago
What is 23% of 200? Please help
Effectus [21]

Answer:

46

Step-by-step explanation: .23 (200) = 46

6 0
3 years ago
Read 2 more answers
A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H
andrey2020 [161]
Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

\bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentrated\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{5\% alloy}&x&0.05&0.05x\\&#10;\textit{30\% alloy}&y&0.30&0.3y\\&#10;-----&-----&-------&-------\\&#10;mixture&100&0.15&15&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+y=100\implies \boxed{y}=100-x\\&#10;0.05x+0.3y=15\\&#10;----------\\&#10;0.5x+0.3\left( \boxed{100-x} \right)=15&#10;\end{cases}

solve for "x"

what's "y"? well, y = 100 - x
4 0
3 years ago
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