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3 years ago

A watermelon seed is 0.4cm long. How far would a line of 122 watermelon seeds stretch

1 answer:

4 0

Your answer is .448 meters

(4mm) (112) = 448mm
There are 1000mm in 1 meter so we want to divide 448 by 1000.
(448mm) / (1000 mm/m) = .448 meters

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12.

IrinaVladis [17]

Answer:

Length of the room is 180 ft

Step-by-step explanation:

We have a rectangular room with dimensions:

width = 70 ft and length "x" (unknown)

Perimeter of a rectangle is 2*w + 2*x and according to problem statement 500 ft of lights will fit exactly in room perimeter then:

2*70 + 2*x = 500

140 + 2*x = 500

2*x = 500 - 140

2*x = 360

x = 360/2

x = 180 ft

5 0

3 years ago

Tju [1.3M]

Answer:

Step-by-step explanation:

Rationalize the denominator of b. So, multiply the numerator and denominator by $\sqrt{x}$

$b = \frac{(1-2\sqrt{x}) *\sqrt{x}}{\sqrt{x}*\sqrt{x} }=\frac{1*\sqrt{x} -2\sqrt{x} *\sqrt{x} }{\sqrt{x} *\sqrt{x} }\\\\=\frac{\sqrt{x} -2x}{x}\\$

Now, find a +b

$a +b = \frac{2x+\sqrt{x} }{x}+\frac{\sqrt{x} -2x}{x}\\\\=\frac{2x+\sqrt{x} +\sqrt{x} -2x}{x}$

Combine like terms

$= \frac{2x-2x+\sqrt{x} +\sqrt{x} }{x}\\\\=\frac{2\sqrt{x} }{x}$

Now find (a + b)²

(a +b)² = $(\frac{2\sqrt{x} }{x})^{2}$

$= \frac{2^{2}*(\sqrt{x} )^{2}}{x^{2}}\\\\= \frac{4* x}{x^{2}}\\\\= \frac{4}{x}$

Hint: $\sqrt{x} *\sqrt{x} =\sqrt{x*x}=x$

5 0

3 years ago

Given the function defined in the table below, find the average rate of change, in the simplest form, of the function over the i

vekshin1

Answer:

im stuck on that question too funny bc im in your class and caught u cheating

Step-by-step explanation:

4 0

3 years ago

How to factor the tens from 30x40

Mariana [72]

10(3+4)= 30+40

I factored the 10 and put it on the outside

6 0

3 years ago

Read 2 more answers

What equation models the data in the table if d = number of days and c = cost?

dedylja [7]

Answer:

c=3d

Step-by-step explanation:

What equation models the data in the table if d = number of days and c = cost? Days Cost 2 6 3 9 5 15 6 18

Answer: An equation is a statement used to show the relationship between variables and shows the equality between two expressions. We want to find the relationship between the number of days and the cost.

Given that:

Days Cost

2 6

3 9

5 15

6 18

Lets take the ratio of days to cost using the first row:

$\frac{d}{c}=\frac{2}{6}\\ \frac{d}{c}=\frac{1}{3}\\c=3d$

The relationship c = 3d is true for all values of days and cost

3 0

3 years ago