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3 years ago

A watermelon seed is 0.4cm long. How far would a line of 122 watermelon seeds stretch

1 answer:

4 0

Your answer is .448 meters

(4mm) (112) = 448mm
There are 1000mm in 1 meter so we want to divide 448 by 1000.
(448mm) / (1000 mm/m) = .448 meters

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Suppose we want to write 2/5

Basile [38]

Answer:

you must multiply the numerator and denominator by 6

Step-by-step explanation:

because 5 x 6 = 30

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3 years ago

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Simplify -(-2a + 13) + (-9a - 2) - (-7a - 3)

nadya68 [22]

-12 hope it helps :)

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3 years ago

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In a flight of 600 km, the speed of the aircraft was slowed down due to bad weather. The average speed of the trip was decreased

UkoKoshka [18]

The average speed would be 600 km/hr.

Step-by-step explanation:

Let the original speed be 'x'

Let the decreased speed be 'x-200'

Distance = 600 km

Time increased by 30 minutes

According to question, it becomes,

$\dfrac{600}{x-200}-\dfrac{600}{x}=\dfrac{30}{60}\\\\\dfrac{x-(x-200)}{x^2-200x}=\dfrac{1}{2\times 600}\\\\\dfrac{200}{x^2-200x}=\dfrac{1}{1200}\\\\240000=x^2-200x\\\\x^2-200x-240000=0\\\\x=600,-400$

So, The average speed would be 600 km/hr.

5 0

3 years ago

The expression (3x^2)^4/9x^3 is equivalent to which other expression

maksim [4K]

$\frac{(3x^2)^4}{9x^3}=\frac{3^4x^{2\cdot4}}{9x^3}=\frac{81x^8}{9x^3}=9x^{8-3}=9x^5$

5 0

3 years ago

I need help if you can that would be great thank you

liq [111]

Answer:

Simplifying the expression $(3\:.\:2)^5\div (3^2\:.\:2^3)$ so, there is only one power of each base we get $\mathbf{3^3\:.\:2^2}$

Option D is correct answer.

Step-by-step explanation:

We need to simply the expression $(3\:.\:2)^5\div (3^2\:.\:2^3)$ so, there is only one power of each base.

Solving:

$(3\:.\:2)^5\div (3^2\:.\:2^3)$

We can write it as:

$\frac{(3\:.\:2)^5}{3^2.2^3}$

Now using exponent rule: $(a\:.\:b)^m=a^m\:.\:b^n$

$\frac{3^5\:.\:2^5}{3^2.2^3}$

Now using the exponent rule: $\frac{a^m}{a^n}=a^{m-n}$ the bases should be same

$3^{5-2}\:.\:2^{5-3}\\=3^3\:.\:2^2$

So, simplifying the expression $(3\:.\:2)^5\div (3^2\:.\:2^3)$ so, there is only one power of each base we get $\mathbf{3^3\:.\:2^2}$

Option D is correct answer.

5 0

2 years ago