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likoan [24]
4 years ago
11

Determining the Vertex of a Parabola from Its Graph

Mathematics
2 answers:
murzikaleks [220]4 years ago
8 0

Answer:

(-3, -4)

Step-by-step explanation:

The solid circles along the parabola are:

(-6, 5), (-5, 0), (-4, -3), (-3, -4), (-2, -3), (-1, 0), (0, 5).

Although on observation, the minimum point of y occurs at (-3, -4), we can also confirm through the function.

The x-intercept of the parabola are -5 and -1.

x=-5 or x=-1

x+5=0 or x+1=0

(x+5)(x+1)=0

x^2+5x+x+5=0\\x^2+6x+5=0

The Vertex of the equation occurs at the axis of symmetry, x=-\dfrac{b}{2a}

In f(x)=x^2+6x+5, a=1, b=6

Axis of Symmetry, x=-\dfrac{6}{2}=-3

f(-3)=(-3)^2+6(-3)+5=9-18+5=-4

Therefore, we can confirm that the vertex is (-3,-4) as stated earlier.

adell [148]4 years ago
7 0

Answer:

( -3 , -4 )    

Step-by-step explanation:

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A counter top is 18 feet long and 3 feet wide. What is the area of the counter top in square meters? Use the conversion 1 foot =
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Step-by-step explanation:

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Solution:

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But given data is in feet so we will first convert feet into meters.

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