B : 30
95+55 = 150
180-150 = 30
-6 + 6 = 0
0 + -2x = 12 + 6 -2x = 12 + 6<span>4x+2(x-3)=8x+12 is our main problem right? so...
</span><span>4x + (-3 * 2 + x * 2) = 8x + 12
4x + (-6 + 2x) = 8x + 12
</span><span>So next we do:
</span><span>-6 + 4x + 2x = 8x + 12
Reorder the terms :) </span><span>-6 + 6x = 12 + 8x
</span>Now were going to solve for x
<span>-6 + -2x = 12 + 8x + -8x
</span><span>8x + -8x = 0
-6 + -2x = 12 + 0
-6 + -2x = 12
</span>-6 + 6 = 0
0 + -2x = 12 + 6
-2x = 12 + 6=
<span>-2x = 18
so now were just going to divide each side by -2
and so thats going to be like this
-2x = 18</span>
/ -2 /-2
0 -9
so whats left over is x = -9
So your answer is A.
Answer:
The measure of ∠GKH is 27°
Step-by-step explanation:
- In the isosceles triangle, the base angles are equal in measures
- The measure of an exterior angle at a vertex of a triangle equals the sum of the measures of two opposite interior angles
In Δ HJK
∵ HJ = JK
→ That means the triangle is isosceles
∴ Δ HJK is an isosceles triangle
∵ ∠JHK and ∠JKH are base angles
→ By using the first rule above
∴ m∠JHK = m∠JKH
∵ m∠HJK = 70°
∵ m∠JHK + m∠JKH + m∠HJK = 180° ⇒ interior angles of a triangle
∴ m∠JHK + m∠JKH + 70 =180
→ Subtract 70 from both sides
∴ m∠JHK + m∠JKH = 110
→ Divide their sum by 2 to find the measure of each one
∴ m∠JHK = m∠JKH = 110 ÷ 2 = 55°
∵ ∠JHK is an exterior angle of ΔGHK at vertex H
∵ ∠HGK and ∠GKH are the opposite interior angles to ∠JHK
→ By using the 2nd rule above
∴ m∠JHK = m∠HGK + m∠GKH
∵ m∠JHK = 55°
∵ m∠HGK = 28°
∴ 55 = 28 + m∠GKH
→ Subtract 28 from both sides
∴ 27° = m∠GKH
∴ The measure of ∠GKH is 27°
