Y=mx+c
m1 x m2 = - 1 for perpendicular lines
m= -1/5
so now y= - 1/5x + c
Substitute given coordinate
3= (-1/5 × 3) +c
3= -3/5 + c
add 3/5 to both sides
2.6 (a.k.a 18/5) = y
So therefore:
y=(-x+18)/5
I think this is correct
Answer:
Scatter plot with line of best fit of y equals 0.75x plus five.
The line of best fit is y = 0.75x + 5.
Choose the best representation for the slope.
The slope of the line of best fit shows that each additional minute, the distance increases by 0.75 feet.
The slope of the line of best fit shows that each additional minute, the distance decreases by 5 feet.
The slope of the line of best fit shows that each additional minute, the distance decreases by 0.75 feet.
The slope of the line of best fit shows that each additional minute, the distance increases by 5 feet.
Step-by-step explanation:
A1 = 9
r = 2/3
An = ar^{n - 1}
An = 9.(2/3)^{n - 1}
Option → C
Given that the equation to find the height of the firework is
h(t) = at² + vt + h₀
with a = -16 ft/s² and v = 128 ft/s. In addition, since the firework starts from the ground, then the initial height, h₀, is equal to 0. Substituting these values, we have
h(t) = -16t² + 128t + 0 = -16t² + 128t
Seeing that h(t) is a quadratic function, then it forms a parabola. To find its maximum height, we can compute for the parabola's vertex.
To find the vertex's x-coordinate, we can use
t = -b/2a = (-128)/(2 · -16) = -128/-32 = 4
Since, it takes 4 seconds for the firework to reach its maximum height, then the maximum height it reaches is equal to h(4). Hence, we have
h(4) = -16(4)² + 128(4) = -16(16) + 512 = 256
Hence, the highest that the firework can reach is equal to 256 ft.
Answer: A. 256 ft