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anzhelika [568]
3 years ago
11

Which ordered pair is a solution to the equation y = 6x - 4?

Mathematics
1 answer:
nevsk [136]3 years ago
5 0
y= 2 and x= 1
because 6 * 1 = 6
6 - 4 = 2
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What two values add up to be -11 and multiply to be 28?
Troyanec [42]

Answer:

-7 and -4

Step-by-step explanation:

28= -7*-4

-11= -7+-4

6 0
3 years ago
Sarah wants to hang a mirror in her room. The mirror and frame must have an area of 15 square feet. The mirror is 3 feet wide an
Colt1911 [192]

Answer:

x^2 + 7x - 3 = 0

Step-by-step explanation:

I think you meant "width of the frame" from outside of frame to outside of mirror.

Let x represent the width of the frame.

Area of mirror is (3 ft)(4 ft) = 12 ft^2.  Total area of mirror and frame is 15 ft^2.  The 3 ft^2 difference is the area of the frame.

But you were asked to find a quadratic equation that would give you the "width" of the frame.  

The "new" width would be 3 + x and the "new" height would be 4 + x.

Then the area of the mirror and frame together would be

A = (3 + x)(4 + x) = 15 ft^2, or

      12 + 7x + x^2 = 15 ft^2, or

x^2 + 7x - 3 = 0.  This is the desired quadratic equation.

When answer choices are given, please share them when you post a question.  Thank you.

4 0
4 years ago
Harry goes to Hogwarts School of Witchcraft and Wizardry. He can travel to school and back in 333 different ways: by the Hogwart
Morgarella [4.7K]

Answer: The answer is A and C.

Step-by-step explanation:

I got it right on Khan. :)

5 0
3 years ago
11r+7s help me please
Maru [420]

Answer: First term = 11r and  second term= 7s

The coefficient in first term = 11

The coefficient in second term =7

Step-by-step explanation:

The given expression 11r + 7s is with two terms i.e. a binomial expression with variables r and s

Here the first term = 11r

And the coefficient of r in term =11

The second term= 7s

The coefficient of s in second term=7

The coefficients are the numbers that multiply the variables .

6 0
3 years ago
Find the units digit of the following within the indicated number base: $(14_8)^2$
amid [387]
Can you say what is the line between the 14 and 8
4 0
3 years ago
Read 2 more answers
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