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anzhelika [568]
2 years ago
11

Which ordered pair is a solution to the equation y = 6x - 4?

Mathematics
1 answer:
nevsk [136]2 years ago
5 0
y= 2 and x= 1
because 6 * 1 = 6
6 - 4 = 2
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Rashad has 24 jolly ranchers and 56 blow pops for making treat bags for his sisters birthday party. what is the largest number o
Vinil7 [7]

The largest numbers of snacks bag can be number 80 which consists of 24 jolly ranchers and 56 blow pops.

Given that Rashad has 24 jolly ranchers and 56 blow pops for making treat bags for his sister's birthday party and asked to find out the largest numbers of snacks in the bag.

There are 24 jolly ranchers and 56 blow pops and For the maximum numbers of snacks in the bag can be 24 jolly ranchers and 56 blow pops.

The maximum numbers of snacks that can be filled in a snacks bag is 24 jolly ranchers and 56 blow pops.

Therefore,The largest numbers of snacks bag can be number 80 which consists of 24 jolly ranchers and 56 blow pops.

Learn more about numbers here:

brainly.com/question/17429689

#SPJ4

7 0
1 year ago
Need help :) i’m bad at math lol
Andrei [34K]

Answer:

i think it is the last one

Step-by-step explanation:

-2/25^3x^3

5 0
3 years ago
Suppose 8 books stacked on top of one another. Each book is 1 5/9 inches thick. How high is the stack of books?
Mekhanik [1.2K]

Answer:

Step-by-step explanation:

12.4

you have to multiply 1 5/9 times 8

8 0
3 years ago
Fill in the blank to complete the sentence. A square with area 49 cm² has perimeter cm ok 2 Asquare with area 49 cm? has perimet
klasskru [66]

Answer:

7 cm

Step-by-step explanation:

it is a square so sqrt(49)=7, and the side lengths are 7

7 0
2 years ago
−2x=x^2−6
Iteru [2.4K]

Step-by-step explanation:

Example 1

Solve the equation x3 − 3x2 – 2x + 4 = 0

We put the numbers that are factors of 4 into the equation to see if any of them are correct.

f(1) = 13 − 3×12 – 2×1 + 4 = 0 1 is a solution

f(−1) = (−1)3 − 3×(−1)2 – 2×(−1) + 4 = 2

f(2) = 23 − 3×22 – 2×2 + 4 = −4

f(−2) = (−2)3 − 3×(−2)2 – 2×(−2) + 4 = −12

f(4) = 43 − 3×42 – 2×4 + 4 = 12

f(−4) = (−4)3 − 3×(−4)2 – 2×(−4) + 4 = −100

The only integer solution is x = 1. When we have found one solution we don’t really need to test any other numbers because we can now solve the equation by dividing by (x − 1) and trying to solve the quadratic we get from the division.

Now we can factorise our expression as follows:

x3 − 3x2 – 2x + 4 = (x − 1)(x2 − 2x − 4) = 0

It now remains for us to solve the quadratic equation.

x2 − 2x − 4 = 0

We use the formula for quadratics with a = 1, b = −2 and c = −4.

We have now found all three solutions of the equation x3 − 3x2 – 2x + 4 = 0. They are: eftirfarandi:

x = 1

x = 1 + Ö5

x = 1 − Ö5

Example 2

We can easily use the same method to solve a fourth degree equation or equations of a still higher degree. Solve the equation f(x) = x4 − x3 − 5x2 + 3x + 2 = 0.

First we find the integer factors of the constant term, 2. The integer factors of 2 are ±1 and ±2.

f(1) = 14 − 13 − 5×12 + 3×1 + 2 = 0 1 is a solution

f(−1) = (−1)4 − (−1)3 − 5×(−1)2 + 3×(−1) + 2 = −4

f(2) = 24 − 23 − 5×22 + 3×2 + 2 = −4

f(−2) = (−2)4 − (−2)3 − 5×(−2)2 + 3×(−2) + 2 = 0 we have found a second solution.

The two solutions we have found 1 and −2 mean that we can divide by x − 1 and x + 2 and there will be no remainder. We’ll do this in two steps.

First divide by x + 2

Now divide the resulting cubic factor by x − 1.

We have now factorised

f(x) = x4 − x3 − 5x2 + 3x + 2 into

f(x) = (x + 2)(x − 1)(x2 − 2x − 1) and it only remains to solve the quadratic equation

x2 − 2x − 1 = 0. We use the formula with a = 1, b = −2 and c = −1.

Now we have found a total of four solutions. They are:

x = 1

x = −2

x = 1 +

x = 1 −

Sometimes we can solve a third degree equation by bracketing the terms two by two and finding a factor that they have in common.

6 0
3 years ago
Read 2 more answers
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