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3 years ago

I need help!!

Mathematics

1 answer:

lapo4ka [179]3 years ago

6 0

Answer:

.363

Step-by-step explanation:

I believe that the answer is .363, I didn't round anything

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What is the area of 3 5\7ft by 2 6\7ft

erica [24]

3 5/7 x 2 6/7
= 3.71428564 x 2.8571428
= 10.6 ft^2 (3 sig. fig.)

4 0

3 years ago

Can someone help me with the questions in the picture?

jolli1 [7]

Answer:

1. x= -4

2. x= 18

3. x= -15

4. x = 6

Step-by-step explanation:

Use relationship of angles to create equations and solve for x

6 0

3 years ago

Read 2 more answers

Help !! Please I can’t find the answer

SVETLANKA909090 [29]

Answer:

$\large\boxed{r^2=(x+5)^2+(y-4)^2}$

Step-by-step explanation:

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have diameter endpoints.

Half the length of the diameter is the length of the radius.

The center of the diameter is the center of the circle.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the given points (-8, 2) and (-2, 6):

$d=\sqrt{(6-2)^2+(-2-(-8))^2}=\sqrt{4^2+6^2}=\sqrt{16+36}=\sqrt{52}$

The radius:

$r=\dfrac{d}{2}\to r=\dfrac{\sqrt{52}}{2}$

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$x=\dfrac{-8+(-2)}{2}=\dfrac{-10}{2}=-5\\\\y=\dfrac{2+6}{2}=\dfrac{8}{2}=4$

$(-5,\ 4)\to h=-5,\ k=4$

Finally:

$(x-(-5))^2+(y-4)^2=\left(\dfrac{\sqrt{52}}{2}\right)^2\\\\(x+5)^2+(y-4)^2=\dfrac{52}{4}\\\\(x+5)^2+(y-4)^2=13$

5 0

3 years ago

28 is equal to how many hundredths and tenths

natita [175]

Answer:

0 hundredths. 2 tenths and 8 ones

8 0

3 years ago

Read 2 more answers

How to do this plzz

gtnhenbr [62]

Answer:

88 cm²

Step-by-step explanation:

The perimeter of each square is 22 cm

we should divide by 4 to get the length of the square

22/4=5.5 cm

so we should multiply by 2 to get the length of the rectangle

5.5*2= 11

the perimeter is :

P= 5.5+5.5+5.5+11+11+5.5+5.5+11+11+5.5+5.5+5.5 = 88 cm²

8 0

3 years ago