Answer:
40
Step-by-step explanation:
do 320=8t
divide 320 by 8 to isolate t
t = 40
 
        
             
        
        
        
Answer:
4k + 2j + 1
Step-by-step explanation:
5k + 3 + 2j – 2 – k = 
5k - k + 2j + 3 - 2
4k + 2j + 1
 
        
                    
             
        
        
        
The correct order would be: 
5/64 x 3, 1/16 x 3, 3/32 x 4, 11/64 x 4, 7/16 x 3, 3/4 x 2, 3/8 x 4, 1 7/8 x 4, 2.25 x 2, 1.5 x 4, 3 3/8 x 3, 3.75 x 3 
First we have to take all of the numbers and do the multiplication. It's often easiest to turn them in to decimals so that you have a common form. 
3/32 x 4 = 3/8 = .375
3/4 x 2 = 3/2 = 1.5
1 7/8 x 4 = 15/4 = 3.75
2.25 x 2 = 4.5
1.5 x 4 = 6
3/8 x 4 = 3/2 = 1.5
5/64 x 3 = 5/32 = .156
3.75 x 3 = 11.25
1/16 x 3 = 3/16 = .1875
7/16 x 3 = 21/16 = 1.31
3 3/8 x 3 = 81/8 = 10.125
11/64 x 4 = 11/16 = .687
Now we can use those to put in order. 
5/64 x 3 = 5/32 = .156
1/16 x 3 = 3/16 = .1875
3/32 x 4 = 3/8 = .375
11/64 x 4 = 11/16 = .687
7/16 x 3 = 21/16 = 1.31
3/4 x 2 = 3/2 = 1.5
3/8 x 4 = 3/2 = 1.5
1 7/8 x 4 = 15/4 = 3.75
2.25 x 2 = 4.5
1.5 x 4 = 6
3 3/8 x 3 = 81/8 = 10.125
3.75 x 3 = 11.25
Which if you are looking for without the extra terms, you can check the answer at the top. 
 
        
             
        
        
        
Hello :
<span>3y = x + 6 ...(1)
y – x = 3...(2)
by (2) : y = x+3...(*)
subsct in (1) :
3(x+3) = x+6
3x-x= -9+6
2x= -3
x=-3/2
subsct in (*) : y =-3/2 +3 =3/2</span>
        
                    
             
        
        
        
Answer:
here i finished!
hope it helps yw!
Step-by-step explanation:
The doubling period of a bacterial population is 15 minutes.
At time t = 90 minutes, the bacterial population was 50000.
Round your answers to at least 1 decimal place.
:
We can use the formula:
A = Ao*2^(t/d); where:
A = amt after t time
Ao = initial amt (t=0)
t = time period in question
d = doubling time of substance
In our problem
d = 15 min
t = 90 min
A = 50000
What was the initial population at time t = 0
Ao * 2^(90/15) = 50000
Ao * 2^6 = 50000
We know 2^6 = 64
64(Ao) = 50000
Ao = 50000/64
Ao = 781.25 is the initial population
:
Find the size of the bacterial population after 4 hours
Change 4 hr to 240 min
A = 781.25 * 2^(240/15
A = 781.25 * 2^16
A= 781.25 * 65536
A = 51,199,218.75 after 4 hrs