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2 years ago

I really think it’s B ...Help?

Mathematics

1 answer:

kvv77 [185]2 years ago

7 0

The correct answer is c y-5=4(x-7)

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8. The angle measures of a triangle are shown in the diagram. What is the value of x? A. 20 B. 15. C. 32 D. 40 I WILL GIVE BRAIN

AfilCa [17]

Answer:

D) 40

Step-by-step explanation:

triangles equal to 180 degrees

2x+10+x+50=180

3x+60=180

3x=120

x=40

7 0

10 months ago

Need help asap!!!!!!!

Neporo4naja [7]

Answer:

a) Linear function

b) Linear function

c) Exponential function

d) Exponential function

Step-by-step explanation:

a) The number of hours in a day increases constantly with 60 minute intervals

b) Constant speed = same distance traveled per given time - so it's linear

c) If a population doubles every y years, it means that the population is being raised exponentially - not at a constant rate, but more each year

d) Same as c

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2 years ago

I feel like everyone on this app has just given up, because no one has been helping me with any of my math stuff. And it's just

Darina [25.2K]

Answer:

aw, i <3 you to ;)

if you need me let me know

okay?

;)

5 0

2 years ago

Read 2 more answers

If your starting salary were $35,000 and you received a 6% increase at the end of every year for 16 years, what would be the tot

guajiro [1.7K]

After 17 years of working you would have $70700

8 0

3 years ago

Let <img src="https://tex.z-dn.net/?f=i" id="TexFormula1" title="i" alt="i" align="absmiddle" class="latex-formula"> be the imag

VLD [36.1K]

$Hey~freckledspots!\\----------------------$

$We~will~solve~for~i^{425}!$

$Rule~of~exponent: a^{b + c} = a^ba^c\\Apply:~i^{425}~=~i^{424}i\\ \\Rule~of~exponent: a^{bc} = (a^{b})^c\\Apply: i^{424} = i(i^2)^{212} \\\\Rule~of~imaginary~number: i^2 = -1\\Apply: i(i^2)^{212} = -1^{212}i\\\\Rule~of~exponent~if~n~is~even: -a^n = a^n\\Apply: -1^{212}i = 1^{212}i\\\\Simplify: 1^{212}i = 1i\\Multiply: 1i * 1 = i\\----------------------\\$

$Now~let's~solve~1^{14}!\\\\Rule~of~exponent: a^{b + c} = a^ba^c\\Apply: i^{14} = (i^2)^7\\\\Rule~of~imaginary~number: i^2 = -1\\Apply: (i^2)^7 = -1^7\\\\Rule~of~exponent~if~n~is~odd: (-a)^n = -a^n\\Apply: -1^7 = -1^7\\\\Simplify: -1^7 = -1\\----------------------\\Now,~we~have: i-1+i^{-14}+i^{44}\\----------------------$

$Now~lets~solve~i^{-14}\\\\Rule~of~exponent: a^{-b} = \frac{1}{a^b} \\Apply: i^{-14} = \frac{1}{i^{14}} \\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: \frac{1}{i^{14}} = \frac{1}{(i^2)^7}\\ \\Rule~of~imagianry~number: i^2 = -1\\Apply: \frac{1}{(i^2)^7} = \frac{1}{-1^7} \\\\Simplify: \frac{1}{-1^7} = \frac{1}{-1} \\\\Rule~of~fractions: \frac{a}{-b} = -\frac{a}{b} \\Apply: \frac{1}{-1} = -\frac{1}{1} = -1\\----------------------\\Now,~we~have: i-1-1+i^44\\----------------------$

$Now~let's~solve~i^{44}!\\\\Rule~of~exponent: a^{bc} = (a^b)^c\\Apply: i^{44} = (i^2)^{22}\\\\Rule~of~imaginary~numbers: i^2 = -1\\Apply: (i^2)^{22} = -1^{22}\\\\Rule~of~exponent~if~n~is~even: (-a)^n = a^n\\Apply: -1^{22} = 1^{22}\\\\Simplify: 1^{22} = 1\\----------------------\\Now,~we~have~i-1-1+1\\----------------------$

$Now~let's~simplify~the~expression!\\\\= i-1-1+1 \\= 1 + i -2\\= -1+i\\----------------------$

$Answer:\\\large\boxed{-1+i}\\----------------------$

$Hope~This~Helped!~Good~Luck!$

8 0

3 years ago

Read 2 more answers