Answer:
Step-by-step explanation:
Given data
Total units = 250
Current occupants = 223
Rent per unit = 892 slips of Gold-Pressed latinum
Current rent = 892 x 223 =198,916 slips of Gold-Pressed latinum
After increase in the rent, then the rent function becomes
Let us conside 'y' is increased in amount of rent
Then occupants left will be [223 - y]
Rent = [892 + 2y][223 - y] = R[y]
To maximize rent =

Since 'y' comes in negative, the owner must decrease his rent to maximixe profit.
Since there are only 250 units available;
![y=-250+223=-27\\\\maximum \,profit =[892+2(-27)][223+27]\\=838 * 250\\=838\,for\,250\,units](https://tex.z-dn.net/?f=y%3D-250%2B223%3D-27%5C%5C%5C%5Cmaximum%20%5C%2Cprofit%20%3D%5B892%2B2%28-27%29%5D%5B223%2B27%5D%5C%5C%3D838%20%2A%20250%5C%5C%3D838%5C%2Cfor%5C%2C250%5C%2Cunits)
Optimal rent - 838 slips of Gold-Pressed latinum
Answer:
2 solutions
Step-by-step explanation:
x^4-6x^2-7=0
Replace x^2 by y
(x^2)^2-6x^2-7=0
y^2-6y-7=0
D=b^2-4ac= (-6)^2-4*1*(-7)= 36+28=64
sqrtD=8
y1=(-b-sqrtD)/2a=-2/2=-1
y2= (-b+sqrtD)/2a=14/2=7
x^2=-1(n0 roots) x^2=7 x=sqrt7 or x=-sqrt7
2 roots
Answer:
its 0 because when 2 on the x-axis is y0