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2 years ago

HELP THIS IS DUE IN 1:00 PM AND I WILL GIVE BRAINLIEST

Mathematics

1 answer:

amid [387]2 years ago

5 0

Answer:

1) They were multiplied by one power of ten because 2.5x 1^10 is 25, and so that it is easier to divide.

19.625/ 2.5 * 10/10 = 196.25/25

Hope this helps plz hit the crown ;D

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Alina has just received 333 video games for her birthday to add to her existing 121212 video games. A week later she went to the

Katarina [22]

[(121212+333)(2)]+555

7 0

2 years ago

if you were to solve the following system by substitution, what would be the best variable to solve for and from what equation?

Romashka-Z-Leto [24]

Answer:

see below

Step-by-step explanation:

2x+8y=12 3x-8y=11

If we have to solve by substitution, Take the first equation and divide by 2

2x/2 + 8y/2 =12/2

x+4y = 6

Then subtract 4y from each side

x = 6 -4y

Then substitute this into the second equation

This is best solved by elimination

2x+8y=12

3x-8y=11

----------------

5x = 36

x = 36/5

6 0

2 years ago

Find the radius of convergence, then determine the interval of convergence

galben [10]

The radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series. This can be obtained by using ratio test.

<h3>Find the radius of convergence R and the interval of convergence:</h3>

Ratio test is the test that is used to find the convergence of the given power series.

First aₙ is noted and then aₙ₊₁ is noted.

For ∑ aₙ, aₙ and aₙ₊₁ is noted.

$\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }|$ = β

If β < 1, then the series converges

If β > 1, then the series diverges

If β = 1, then the series inconclusive

Here $a_{k}$ = $\frac{(x+2)^{k}}{\sqrt{k} }$ and $a_{k+1}$ = $\frac{(x+2)^{k+1}}{\sqrt{k+1} }$

Now limit is taken,

$\lim_{n \to \infty} |\frac{a_{n+1}}{a_{n} }|$ = $\lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }/\frac{(x+2)^{k} }{\sqrt{k} }|$

= $\lim_{n \to \infty} |\frac{(x+2)^{k+1} }{\sqrt{k+1} }\frac{\sqrt{k} }{(x+2)^{k}}|$

= $\lim_{n \to \infty} |{(x+2) } }{\sqrt{\frac{k}{k+1} } }}|$

= $|{x+2 }|\lim_{n \to \infty}}{\sqrt{\frac{k}{k+1} } }}$

= $|{x+2 }|$ < 1

- 1 < ${x+2 }$ < 1

- 1 - 2 < x < 1 - 2

- 3 < x < - 1

We get that,

interval of convergence = (-3, -1)

radius of convergence R = 1

Hence the radius of convergence R is 1 and the interval of convergence is (-3, -1) for the given power series.

Learn more about radius of convergence here:

brainly.com/question/14394994

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5 0

9 months ago

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F(x) = x^2 is stretched vertically by a factor of 4 and shifted 1 unit down.<br><br> equation = ???

LenKa [72]

Answer:

f(x) = 4x² - 1

Step-by-step explanation:

The given function is; f(x) = x²

Now, when stretched vertically by a factor of 4, we have;

f(x) = 4x²

It's now shifted 1 unit down.. Thus, the final function will be;

f(x) = 4x² - 1

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2 years ago

Create an equivalent expressions for each of the following.

Sphinxa [80]

Hope this helps.

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3 years ago

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