Answer:8
Step-by-step explanation:
Area = Length x Width.
simple room measurement
Measure the length using the distance from one wall to the opposite wall.
Measure the width from wall to wall.
Add 2 to 4 inches to each side. This accounts for waste, doors and slanting walls. It’s easy to cut a little off for a perfect fit, but it’s impossible to add without creating unsightly seams.
Multiply the length times the width or enter those into the calculator above. This is your total square footage for that room.
Repeat this process for each room.
NOT SURE HOW MU
Answer:
Step-by-step explanation:
The image below shows step-by-step on how to solve it.
<em>Hope this helps! </em>:)
These are the ones that are not equivalent to eachother. 1. 18/30
2. 8/10
3. 4/9
4. 14/18
5. 10/20
6. 20/32
7. 18/30
Q1. The answers are (–1, 8), (0, 7), (3, 18)
<span>–3x + y ≥ 7
</span>Let's go through all choices:
<span>(–2, –3)
</span>(-3) * (-2) + (-3) ≥ 7
6 - 3 ≥ 7
3 ≥ 7 INCORRECT
(–1, 8)
(-3) * (-1) + 8 ≥ 7
3 + 8 ≥ 7
11 ≥ 7 CORRECT
(0, 7)
(-3) * 0 + 7 ≥ 7
0 + 7 ≥ 7
7 ≥ 7 CORRECT
(1, 9)
(-3) * 1 + 9 ≥ 7
-3 + 9 ≥ 7
6 ≥ 7 INCORRECT
(3, 18)
(-3) * 3 + 18 ≥ 7
-9 + 18 ≥ 7
9 ≥ 7 CORRECT
Q2. The answers are:
5x + 12y ≤ 80
x ≥ 4
<span>y ≥ 0
</span>
<span>x - small boxes
</span><span>y - large boxes
</span>He has x small boxes that weigh 5 lb each and y large boxes that weigh 12 lb each <span>on a shelf that holds up to 80 lb:
5x + 12y </span>≤ 80
Jude needs at least 4 small boxes on the shelf: x ≥ 4
Let's check if y can be 0:
5x + 12y ≤ 80
5x + 12 * 0 ≤ 80
5x + 0 ≤ 80
5x ≤ 80
x ≤ 80 / 5
x ≤ 16
x ≥ 4 can include x ≤ 16
So, y can be 0: y ≥ 0
