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3 years ago

Find an equation of the line perpendicular to the graph of 14x-7y=8 that passing through the point at (-2,5).

Mathematics

1 answer:

MAXImum [283]3 years ago

7 0

Answer:

2x + 4y = 16.

Step-by-step explanation:

14x - 7y = 8

Convert to slope-intercept form:

-7y = -14x + 8

y = 2x - 8/7

The slope is 2 so the line perpendicular to it has a slope of -1/2, so we have:

y = 1/2x + c

This line passes through the point (-2, 5) so:

5 = -1/2* (-2) + c

5 = 1 + c

c = 5 - 1 = 4

So our equation is y = -1/2x + 4.

Convert to standard from

4y = -2x + 16

2x + 4y = 16.

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Answer:

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Step-by-step explanation:

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Answer:

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