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PilotLPTM [1.2K]
3 years ago
14

In ΔDEF, the measure of ∠F=90°, EF = 2.3 feet, and FD = 2.9 feet. Find the measure of ∠D to the nearest tenth of a degree.

Mathematics
1 answer:
Phoenix [80]3 years ago
8 0

Answer:

\theta=38.42 \textdegree

Step-by-step explanation:

From the question we are told that:

Angle of F \angle F=90 \textdegree

Length of EF = 2.3 feet,

Length of FD= 2.9 feet,

Generally the equation for Angle D \theta is mathematically given by

Since \angle F=90.The triangle  is a right angle Triangle

Therefore

 tan \theta=\frac{EF}{FD}

 tan \theta=\frac{2.3}{2.9}

 \theta=tan^{-1} 0.793

 \theta=38.42 \textdegree

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use the fact that 10^3 = 2^10 to mentally find a vaule of n for which 2^n > 10^50 & 10^n > 2^300
Rudiy27
2^n>10^{50}=10^{3\cdot16+2}=10^2(10^3)^{16}=10^2(2^{10})^{16}=5^22^{162}
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