(13x + 2x³ - 6 - x²)÷(x-3)

Jeremiah always rides his bike to and from work. The total

Katen [24]

From the computation done, the total kilometers that he uses last month will be 262.8 kilometers.

The total length of a trip to and from work is 14.6 kilometers and last month, Jeremiah worked 18 days.

Therefore, the kilometers that he rode his bike to and from work last month will be;

= 14.6 × 18.

= 262.8 kilometers.

Learn more about equations on:

brainly.com/question/13763238

7 0

2 years ago

Hadley has 3/6 of a box of white envelopes and 1/3 of a box of gray envelopes. When full, each box of envelopes has the same num

QveST [7]

Answer:

<u>The two statements that apply are A and B.</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

White envelopes Hadley has = 3/6 of a box

Gray envelopes Hadley has = 1/3 of a box

When full, each box of envelopes has the same number of envelopes

Hadley said she has 4/9 of a box when she puts the white envelopes and gray envelopes together.

2. Which statements describe this situation? Select the two statements that apply.

Let's add 3/6 and 1/3

3/6 + 1/3 = 3/6 + 2/6 = 5/6

A. Hadley’s answer is incorrect, because 3/6 is equal to 1/2 , and 4/9 is less then 1/2 . This is correct.

B. Hadley's answer is incorrect, because 3/6 plus 1/3 equals 5/6. This is correct.

C. Hadley's answer is incorrect, because 3/6 plus 1/3 equals 2/6. This is wrong

D. Hadley's answer is correct, because 3 and 1 is 4, and 6 and 3 is 9. This is wrong.

<u>The two statements that apply are A and B.</u>

3 0

3 years ago

Why is 1/3 bigger than 4/5

UkoKoshka [18]

1/3 is in fact NOT larger than 4/5. 4/5 is larger than 1/3.

4 0

3 years ago

Read 2 more answers

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

What is the formula for elimintation

inysia [295]

Answer:

The elimination method for solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation. So if you have a system: x – 6 = −6 and x + y = 8, you can add x + y to the left side of the first equation and add 8 to the right side of the equation.

3 0

2 years ago

Read 2 more answers

(13x + 2x³ - 6 - x²)÷(x-3)​

(13x + 2x³ - 6 - x²)÷(x-3)