Which of the following is a proportion? 9/12 = 8/10 3/4 = 9/12 6/8 = 8/12 12/18 = 19/16

T+2/3t-1/3 I really need this question to be answered

Murrr4er [49]

Equation:

x(x - 5) + 3(x + 5)

Steps:

x(x - 5) + 3(x + 5)

Expand:

x(x - 5 ): x^2 - 5x

x^2 - 5x + 3(x + 5)

Expand:

3(x + 5): 3x + 15

x^2 - 5x + 3x + 15

Add Similar Elements:

-5x + 3x

= -2x

Answer x^2 - 2x + 15 Doesn't Factor

Hope that helps!!! : )

5 0

3 years ago

A school group wants to rent part of a bowling alley to have a party. The bowling alley costs $500 to rent, plus an additional c

Firlakuza [10]

Answer:

If there are N students, the total cost will be:

C(N) = $500 + $5*N.

And we want the amount that each student pays to be equal or less than $15.

then:

C(N)/N ≤ $15.

Then the inequality that represents this situation is:

($500 + $5*N)/N ≤ $15.

Now, let's solve this:

($500 + $5*N) ≤ $15*N

$500 ≤ $15*N - $5*N

$500 ≤ $10*N

$500/$10 ≤ N

50 ≤ N

So the minimum number of students needed is 50.

7 0

3 years ago

I need help asap

Zielflug [23.3K]

Answer:

Option 4

Step-by-step explanation:

So formula of voulme of the cube is a³

We have the side length is 6x

So sub the value in formula we get 216x³

3 0

3 years ago

Read 2 more answers

PLEASE HELP GUYS i am struggling so much, two questions

ankoles [38]

Answer: the equation of the standard parabola

1) $(y-6)^2 = 4 (x-1)$

The equation of the standard parabola

2) (x+5)^2 = 16(y-2)

Step-by-step explanation:

Explanation

Parabola:-

The set of points in a plane whose distance from a fixed point and a constant ratio to their corresponding perpendicular distance from a fixed straight line is a conic.

Let S be a fixed point and l be a fixed straight line from any point P,the perpendicular PM is drawn to the line 'l'

The locus of P such that $\frac{SP}{PM} = constant$
The fixed point 'S' is called the Focus.
The fixed line'l 'is called the directrix of the conic
The constant ratio is known as the eccentricity, denoted by 'e'
If e=1 , the conic is called a parabola

1) Step 1 :-

Given the focus S = (2,6) and directrix is x=0

we know that $\frac{SP}{PM}=1$

now cross multiplication , we get

$SP = PM$

squaring on both sides,we get

$SP^{2} = PM^2$

step 2:-

now using distance formula is

$\sqrt(((x_{2}-x_{1})^2+(y_{2} -y_{1} )^2)$

Given S =(2,6) and P(x,y) be any point on parabola

$SP^2 = (x-2)^2+(y-6)^2$ ........(1)

Now using perpendicular distance formula

let P(x , y ) be any point on the parabola

$\frac{ax_{1}+by_{1}+c }{\sqrt{a^2+b^2} }$

Given the directrix is x =0 and P(x,y) be any point on parabola

$PM^2 = \frac{x^2}{\sqrt{1}^2 }$ ......(2)

equating equation(1) and equation (2), on simplification

we get $(x-2)^2+(y-6)^2 = x^2$ .....(3)

apply $(a-b)^2 = a^2+ b^2+2 ab$

now the equation (3) is

$(y-6)^2 = 4 x-4$

now the standard form of parabola is

$(y-k)^2 = 4 a(x-h)$

Final answer:-

$(y-6)^2 = 4 (x-1)$

2) Explanation:-

step 1:

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

here the given points of 'x'co- ordinates are equal

Therefore the axis AS is parallel to y- axis

now the standard equation of parabola

$(x-h)^2 = 4 a (y-k)$

now you have to find' a' value

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

The distance of $AS = \sqrt{(-5-(-5)^2+(2-6)^2}$

on simplification we get a =4

Final answer :-

the vertex (h,k) = (-5,2) and a=4

$(x-h)^2 = 4 a (y-k)$

The standard parabola is $(x+5)^2 = 16 (y-2)$

5 0

3 years ago

Hottest centralisation

dsp73

Answer:

centralisation mean a direction explain that we often a high how well we cancan predict future actions of others.

Step-by-step explanation:

6 0

3 years ago