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Explanation:</h2><h2>
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The complete question is shown below. As you can see, we know that:
Shapes are congruent if you can turn one into the other by moving, rotating or flipping. If any two triangles have matching side lengths, they're not necessarily congruent. The same happens if they have two matching side lengths, but If triangles have three matching side lengths, then they must be congruent. This is is known as the Side-Side-Side Postulate (SSS). Since in this problem corresponding sides measures the same, therefore we can say that the postulate that applies is:
B. Congruent - SSS
A = l x w
so you know that the length is 3m longer than the width, so you could use a formula to represent that
w = l + 3
you then substitute the second equation into the first to solve for l
70 = l x (l +3)
70 = l^2 + 3l
you could then rearrange the formula and solve for l using the quadratic formula
0 = l^2 + 3l - 70
l = -3 +- (square root (3)^2 - 4(1)(70)) / 2(1)
l = -3 +- (square root 9 + 280) / 2
l = -3 +- (square root 289) / 2
l = -3 +- 17 / 2
then you solve for the two seperate roots
l = -3 + 17 /2
l = 14 / 2
l = 7
or
l = -3 - 17 / 2
l = -20 / 2
l = -10
since a length cannot be negative, this root is not viable. therefore l = 7
to solve for w you would use
w = l + 3
w = 7 + 3
w = 10
hope this helps! if you did not understand a step or concept please let me know!
Answer:
The frequency of A7, which is two octaves above A5, is 3520 (880 x 2 x 2) Hz. The octave term is used in the musical composition to relate the same notes in the higher or lower scale of notes. The note in the one octave higher scale have a doubled frequency than in the neutral scale and The note in the one octave lower scale have a half frequency than in the neutral scale.
Step-by-step explanation:
MARK BRAINLIEST PLEASE!!!!!!!
Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
Answer:
C
Step-by-step explanation:
For any of the functions described above, the only way any of those could be functions is that there has to be a difference value for each x, unless it is the same x-value. If the x is mentioned twice, that is fine, as long as the y point is also the same. If it is different, it is not a function.
