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Mekhanik [1.2K]
3 years ago
5

What the answer to this plz help

Mathematics
2 answers:
Blizzard [7]3 years ago
8 0
The answer should be 9!
Blizzard [7]3 years ago
7 0

Answer:

9

Step-by-step explanation:

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Finish
alex41 [277]

Answer:

What is this? Is that a question? I mean it doesn't seem like one. can you post the proper one?

6 0
3 years ago
Read 2 more answers
I am flooding these ( T_T)
dimulka [17.4K]
That should be 5 2/3 qt.
7 0
3 years ago
Convert 26\%26%26, percent to a fraction in simplest form.
Korolek [52]
26 percent?

A percent is a fraction out of a hundred. 5% is 5 out of one hundred, 20% is 20 out of one hundred, etc.

So 26/100 simplified is 13/50.
6 0
3 years ago
An education researcher claims that 58​% of college students work​ year-round. In a random sample of 400 college​ students, 232
Hatshy [7]

Answer:

The proportion of college students who work​ year-round is 58%.

Step-by-step explanation:

The claim made by the education researcher is that 58​% of college students work​ year-round.

A random sample of 400 college​ students, 232 say they work​ year-round.

To test the researcher's claim use a one-proportion <em>z</em>-test.

The hypothesis can be defined as follows:

<em>H</em>₀: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> = 0.58.

<em>Hₐ</em>: The proportion of college students who work​ year-round is 58%, i.e. <em>p</em> ≠ 0.58. C

Compute the sample proportion as follows:

 \hat p=\frac{232}{400}=0.58

Compute the test statistic value as follows:

 z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.58-0.58}{\sqrt{\frac{0.58(1-0.58)}{400}}}=0

The test statistic value is 0.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

Compute the p-value for the two-tailed test as follows:

 p-value=2\times P(z

*Use a z-table for the probability.

The p-value of the test is 1.

The p-value of the test is very large when compared to the significance level.

The null hypothesis will not be rejected.

Thus, it can be concluded that the proportion of college students who work​ year-round is 58%.

6 0
3 years ago
Find the 50th term of the sequence 5, -2, -9, -16
VARVARA [1.3K]

Answer:

-35

Step-by-step explanation:

it is going backwards by -7 so 5x-7 = -35

6 0
3 years ago
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