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Masja [62]
2 years ago
10

Can someone help me. Please. Algebra.

Mathematics
1 answer:
makkiz [27]2 years ago
7 0

Answer:

what's the question and I'll try my best to answer

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N76 [4]
26/100 or simplified to 13/50
7 0
3 years ago
What is the table of 75​
jarptica [38.1K]

Step-by-step explanation:

75×1=75

75×2=150

75×3=225

75×4=300

75×5=375

75×6=450

75×7=525

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4 0
3 years ago
HURRY<br> answer this question!!
Anna [14]

Answer:

the slope is 0.75

Step-by-step explanation:

you have to find the coordinate of each point then put them in acording to the formula in this case the coordinates are (-2,3) X1 and X2 and (-1,1)y1 and y2

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3 years ago
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SVEN [57.7K]

Answer:

The correct answer is b.)

Step-by-step explanation:

Given:

Sequence  -7, -4, -1, 2, 5.......  => a₁ = -7, a₂ = -4, a₃ = -1, a₄ = 2 and a₅ = 5

We conclude that this sequence is arithmetic series.

First we must find difference d:

d = a₂ - a₁ = a₃ - a₂ = -4 - (-7) = -1 - (-4) = -4 + 7 = -1 + 4 = 3

d = 3

The formula for n-th term of the arithmetic series is:

aₙ = a₁ + (n-1) d

aₙ = -7 + (n-1) 3

God with you!!!

4 0
3 years ago
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Naddik [55]
Check the picture below.

\bf 0=AB^2+6AB-121\implies \stackrel{\textit{using the quadratic formula}}{AB=\cfrac{-6 \pm \sqrt{6^2-4(1)(-121)}}{2(1)}}&#10;\\\\\\&#10;AB=\cfrac{-6 \pm \sqrt{520}}{2}\implies AB=\cfrac{-6 \pm \sqrt{4\cdot 130}}{2}&#10;\\\\\\&#10;AB=\cfrac{-6 \pm \sqrt{2^2\cdot 130}}{2}\implies AB=\cfrac{-6 \pm 2\sqrt{130}}{2}&#10;\\\\\\&#10;AB=-3\pm\sqrt{130}\implies AB=&#10;\begin{cases}&#10;\boxed{-3+\sqrt{130}}\\\\&#10;-3-\sqrt{130}&#10;\end{cases}

since the distance AB cannot be a negative value, thus is not -3-√(130).

3 0
3 years ago
Read 2 more answers
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