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2 years ago

Similar Figures Question 6

Mathematics

1 answer:

Eva8 [605]2 years ago

4 0

Answer:

A) 3

Step-by-step explanation:

divide 77 by 11

you get 7

divide 21 by 7 to find x

x=3

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Which of the following is a result of the construction of a median of a triangle?

stich3 [128]

Answer:

" A side of the triangle is bisected "

Step-by-step explanation:

We have to choose the option which is the result of the construction of a median of a triangle.

When we draw a straight line from a vertex of a triangle to the midpoint of the opposite side then the straight line is called a median of the given triangle.

Hence, when we draw a median of a triangle then it results " A side of the triangle is bisected ". (Answer)

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3 years ago

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What is 3 4/5 rounded to the nearest half

Sphinxa [80]

3 1/2 or 7/2
keep the 3 yards and round the 4/5 to half a yard or 1/2 and just in case turn into a improper fraction

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2 years ago

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What is the volume of the cylinder shown below?

sveta [45]

Answer:

1008pi

Step-by-step explanation:

the formula for volume of a cylinder is pi r squared h

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2 years ago

Michael's car can travel 25 miles on one gallon of gas. The cost of gas is $3.75 per gallon. Which equation could calculate the

Sedaia [141]

T = 3.75n over 25 (make it a fraction)

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3 years ago

Given cos theta = - 2/5 and sin theta < 0, find the six trigonometric values. I need help with this

Lena [83]

Answer:

$\sin\,\theta =-\frac{\sqrt{21} }{5}$

$\tan\,\theta =\frac{\sqrt{21} }{2}$

$\sec\,\theta = \frac{-5}{2}$

$cosec\,\theta =\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{2}{\sqrt{21} }$

Step-by-step explanation:

$\cos\theta =\frac{-2}{5}$

As both $sin\,\theta$ ,

$\theta$ lies in the third quadrant.

In the third quadrant,

$\sin\theta$

$\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}$

$\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}$

$\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}$

$\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }$

$\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }$

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3 years ago