A sphere and a cylinder have the same radius and height. The volume of the cylinder is 27 ft.

Mathematics

1 answer:

rosijanka [135]2 years ago

7 0

Answer:

Step-by-step explanation:

for the cylinder

27π = πr²h = πr²(2r) = 2πr³

for the sphere

V = (4/3)πr² = (2/3)(2πr³) = (2/3)27π

You might be interested in

A bag contains the following marbles: 5

Inessa [10]

Answer:

5:20

Step-by-step explanation:

There are 5 black marbles and 20 brown marbles.

You would put black marbles (5) first, because it came before brown (20) in the list.

5 0

3 years ago

Read 2 more answers

Are ADEF and ARPQ congruent?

kari74 [83]

Answer:

B. Yes. ΔDEF can be mapped to ΔRPQ by a 180° rotation about the origin followed by a translation 2 units down.

Step-by-step explanation:

^^^just did it on edg and got it right.

8 0

3 years ago

The radii of two circles are in the ratio of 3 to 1. Find the area of the smaller circle if the area of the larger circle is 27

Naddik [55]

ANSWER
$3\pi sq.\: in.$

EXPLANATION

Let R be the radius of the bigger circle and r, be the radius of the smaller circle.

Then their ratio is given as,

$R:r=3:1$

We can rewrite it as fractions to get,

$\frac{R}{r} = \frac{3}{1}$

We make R the subject to get,

$R = 3r$

The area of the bigger circle can be found using the formula,

$Area=\pi {r}^{2}$

This implies that,

$Area=\pi ({3r})^{2}$

$Area=9\pi {r}^{2}$

But it was given in the question that, the area of the bigger circle is 27π.

$27\pi=9\pi {r}^{2}$

We divide through by 9π to get,

$3 = {r}^{2}$

This means that,
$r = \sqrt{3}$

The area of the smaller circle is therefore

$= \pi {( \sqrt{3}) }^{2}$

$= 3\pi$