1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ArbitrLikvidat [17]
3 years ago
9

At a local company, 15% of the employees are women. every day, 9% of them bring their lunch to work, while only 3% of the men br

ing lunch. Find the probability that a randomly selected employee
a. is a woman goven that the person brings their lunch to work.
b. brings their lunch to work given that person is a woman.
c. is a woman given that the person brings their lunch to work.
Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

a) 0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.

b) 0.09 = 9% probability that a randomly selected employee brings their lunch to work given that person is a woman.

c) 0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

Questions a/c:

Questions a and c are the same, so:

Event A: Brings lunch to work.

Event B: Is a woman.

Probability of a person bringing lunch to work:

9% of 15%(woman)

3% of 100 - 15 = 85%(man). So

P(A) = 0.09*0.15 + 0.03*0.85 = 0.039

Probability of a person bringing lunch to work and being a woman:

9% of 15%, so:

P(A \cap B) = 0.09*0.15

Desired probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09*0.15}{0.039} = 0.3462

0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.

Question b:

Event A: Woman

Event B: Brings lunch

15% of the employees are women.

This means that P(A) = 0.15

Probability of a person bringing lunch to work and being a woman:

9% of 15%, so:

P(A \cap B) = 0.09*0.15

Desired probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09*0.15}{0.15} = 0.09

0.09 = 9% probability that a randomly selected employee brings their lunch to work given that person is a woman.

You might be interested in
Evaluate P(4,4) <br> Please help me with this asap. It is timed
sweet-ann [11.9K]

Answer:

6 is the answer

:0 HOPE IT HELPED

7 0
3 years ago
Please help !!!!!!!11
musickatia [10]

Step-by-step explanation:

<DBA=180 since it is a straight line

<HBA=73

mHG=73

6 0
3 years ago
Saul in third in line. Enid is last in line. There are 3 children between them. What position is Enid in line?
VLD [36.1K]
Enid is seventh in line
8 0
3 years ago
Use crayons to color to shows at least two of it's parts<br><br><br>​
Luden [163]

Answer:

im not exactly sure what you mean by that, could you please rephrase and expand on the pregunta

Step-by-step explanation:

5 0
2 years ago
PLZ Help
o-na [289]
I have This too sooo hard
5 0
3 years ago
Other questions:
  • The distance from Mark’s apartments to his job is 27 miles. Mark works 5 days per week. How many miles does Mark drive to and fr
    9·1 answer
  • Suppose you travel 378 miles in 7 hours what is you average rate of speed
    6·1 answer
  • I really don't get probability.
    8·1 answer
  • PLEASE HELP ITS GEOMETRY
    13·1 answer
  • What is (5•3) - 18 and can u explain y
    14·2 answers
  • What is the volume of the regular pyramid below?
    11·1 answer
  • Plz help me I don't know what to do!!!!!!
    11·1 answer
  • Plsss help I’ll give u brainlest and 10 points
    13·2 answers
  • 1. Which of the following is the process used by plants to release excess water into the atmosphere?
    12·1 answer
  • Can someone solve this equation.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!