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ArbitrLikvidat [17]
3 years ago
9

At a local company, 15% of the employees are women. every day, 9% of them bring their lunch to work, while only 3% of the men br

ing lunch. Find the probability that a randomly selected employee
a. is a woman goven that the person brings their lunch to work.
b. brings their lunch to work given that person is a woman.
c. is a woman given that the person brings their lunch to work.
Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

a) 0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.

b) 0.09 = 9% probability that a randomly selected employee brings their lunch to work given that person is a woman.

c) 0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

Questions a/c:

Questions a and c are the same, so:

Event A: Brings lunch to work.

Event B: Is a woman.

Probability of a person bringing lunch to work:

9% of 15%(woman)

3% of 100 - 15 = 85%(man). So

P(A) = 0.09*0.15 + 0.03*0.85 = 0.039

Probability of a person bringing lunch to work and being a woman:

9% of 15%, so:

P(A \cap B) = 0.09*0.15

Desired probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09*0.15}{0.039} = 0.3462

0.3462 = 34.62% that a randomly selected employee is a woman given that the person brings their lunch to work.

Question b:

Event A: Woman

Event B: Brings lunch

15% of the employees are women.

This means that P(A) = 0.15

Probability of a person bringing lunch to work and being a woman:

9% of 15%, so:

P(A \cap B) = 0.09*0.15

Desired probability:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.09*0.15}{0.15} = 0.09

0.09 = 9% probability that a randomly selected employee brings their lunch to work given that person is a woman.

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prisoha [69]

Usando la distribución binomial, hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

<h3>¿Qué es la distribución binomial?</h3>

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son:

  • n es el número de ensayos.
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  • x es el número de éxitos

En este problema, hay que:

  • 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal, o sea p = 0.2.
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La probabilidad de que el guardia de seguridad encuentre al menos uno en la base militar restringida es dada por:

P(X \geq 1) = 1 - P(X = 0)

En que:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074

Por eso:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1074 = 0.8926

Hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

Puede-se aprender más a cerca de la distribución binomial en brainly.com/question/25132113

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3 years ago
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-72x^2 + 36 = 3x^3 + 9x^3 + x^2 - 3x + 8       Add 72x^2 to both sides

36 = 12x^3 +   73x^2 - 3x + 8                           Subtract 36 from both sides.

0 = 12x^3 + 73x^2 - 3x - 28      

It does factor, but it is not very nice.

(x + 6.06)(x - 6.09)(x + 0.632)

If there is any kind of error please report it in a note below.

6 0
3 years ago
Check off the methods of differentiation required, and complete the derivative.
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Given:

f(x)=\sqrt[]{5x^2-2}

f(X) will be differentiated by chain rule.

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6 0
1 year ago
A used car dealer sells SUVs and cars. Of all the vehicles, 90% are cars. Of all the vehicles 40% are red cars. What is the prob
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Answer:

44.4%

Step-by-step explanation:

To calculate this, we proceed as follows.

we use the probability equation below;

P(A|B) = P(A and B) / P(B)

Applying the above to the scenario at hand;

P(red | car) = P(red and car) / P(car)

P(red and car) = 40% or simply 40/100 = 0.4

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3 years ago
The play director spent 190190190 hours preparing for a play. That time included attending 353535 rehearsals that took varying a
dybincka [34]

Answer:

The equation 35x+93\frac{3}{4} =190 gives average time spent on 35 rehearsals.

Step-by-step explanation:

We are supposed to find that what question does the equation 35x+93\frac{3}{4} =190 finds answer of.

We can see that 35x represents time spent on 35 rehearsals and 93\frac{3}{4} is time spent on other responsibilities related to play. The sum of these times equals to total time spent on preparing the play.

Now let us solve our equation step by step.

35x+\frac{375}{4} =190

After subtracting 93\frac{3}{4} hours from 190 hours we will get time spent on 35 rehearsals.

35x =190-\frac{375}{4}

35x =\frac{760-375}{4}

35x =\frac{385}{4}

Time spent on 35 rehearsals is 96.25 hours and we are told that each rehearsal took different amount of time. Dividing 96.25 by 35 we will get average time spent on each rehearsal.

x =\frac{96.25}{35}=2.75  

Therefore, equation 35x+93\frac{3}{4} =190 finds average time spent on 35 rehearsals.


7 0
3 years ago
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