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Natalija [7]
3 years ago
6

PLZ Help

Mathematics
1 answer:
o-na [289]3 years ago
5 0
I have This too sooo hard
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Given x and y are integers, explain why the product of the expression and it's conjunct will always be an integer
mars1129 [50]

Answer:

If neither of the two real numbers is zero, then their product is also not zero Suppose also that x is a real number that satisfies the equation The " / " symbol does not always give you a result of an integer, so be careful.pkek, and any other expression for n as a product of prime numbers is identical to this except,.

Step-by-step explanation:

4 0
3 years ago
Help me find the area :)
Andreas93 [3]

Answer:

20.625 ft²

(hope this is right :)

4 0
2 years ago
Which of the following is equivalent to log9w
liraira [26]

what do you meanAnswer:

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP ASAP IM STUCK HELP PLEASE
sasho [114]

Answer:

x>-2  and x<5

-2 <x<5

Step-by-step explanation:

We have open circles at -2 and 5 and are between the two numbers so we have and AND statement. It can be written either

x>-2  and x<5

or

-2 <x<5

6 0
3 years ago
Pls help me, I really dont understand
Stella [2.4K]

Answer:

-2.5x-.5

y=\frac{2}{3}x-1

draw the dotted line (3/7)x-3 and shade below it

Step-by-step explanation:

First, we need the slope

Use the slope formula:

\frac{Y_2-Y_1}{X_2-x_1}=\frac{2-(-8)}{-1-3}=\frac{10}{-4}=-2.5

so we have

y= -2.5x+b

Solve for b by plugging in coordiantes

-8= -2.5(3)+b

-8= -7.5+b

b= -.5

Put it together and get -2.5x-.5

2.)

A line is parallel to another line if they have the same slope (and different y intercepts)

So in the formula y=mx+b we knowe that m= 2/3

Now it's just a matter of solving for B

plug in the required coordinate to do this

-1=(2/3)*0+b

-1= b

Put it all together to get

y=\frac{2}{3}x-1

3.)

put this into slope intercept form

3x-7y>21

3x-21 > 7y

(3/7)x-3 >y

To graph this just draw a dotted line with the equation (3/7)x-3 and shade everything below it (use de_smos if you're stuck)

7 0
3 years ago
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