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lina2011 [118]
3 years ago
6

The approximate curve is an empirical formula equation and the method of finding such an approximating curve is called _________

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
3 0
The answer it Curve Fitting or Arc but I think Curve Fitting just good luck
You might be interested in
What does this mean from the Declaration of Independence
vampirchik [111]
If you don't know what the Declaration of Independence means:
The Declaration of Independence is the statement adopted by the Second Continental Congress meeting at the Pennsylvania State House (Independence Hall) in Philadelphia on July 4, 1776, which announced that the thirteen American colonies,[2] then at war with the Kingdom of Great Britain, regarded themselves as thirteen newly independent sovereign states, and no longer under British rule. Instead they formed a new nation—the United States of America. John Adams was a leader in pushing for independence, which was passed on July 2 with no opposing vote cast. A committee of five had already drafted the formal declaration, to be ready when Congress voted on independence. The term "Declaration of Independence" is not used in the document itself
I hope that helps
7 0
3 years ago
There are currently 17 frogs in a (large) pond. The frog population grows exponentially, tripling every 6 days. How long will it
Tema [17]

Answer:

t=11,11 days

Step-by-step explanation:

F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating \int\limits^ {} \, dF/F =K\int\limits^ {} \, dt⇒ LnF=Kt+c,F=ce^{Kt}; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)), F=ce^{K0} = F=c=17; F=17e^{6K} =51⇒e^{6K} =51/17; K6=ln\frac{51}{17} ; K=ln\frac{51}{17}/6=0.183, so F=17e^{0,183t}, now if F=130, t=? we have:

130=17e^{0.183t} =e^{0.183t} =130/17; 0.183t=ln(130/17); t=ln(130/17)/0.183 = 11,11

8 0
3 years ago
A random sample of 23 items is drawn from a population whose standard deviation is unknown. The sample mean isx⎯ ⎯ x¯ = 840 and
gayaneshka [121]

Answer:

(832.156, \ 847.844)

Step-by-step explanation:

Given data :

Sample standard deviation, s = 15

Sample mean, \overline x = 840

n = 23

a). 98% confidence interval

$\overline x \pm t_{(n-1, \alpha /2)}. \frac{s}{\sqrt{n}}$

$E= t_{( n-1, \alpha/2 )} \frac{s}{\sqrt n}}

$t_{(n-1 , \alpha/2)} \frac{s}{\sqrt n}$

$t_{(n-1, a\pha/2)}=t_{(22,0.01)} = 2.508$

∴ $E = 2.508 \times \frac{15}{\sqrt{23}}$

  $E = 7.844$

So, 98% CI is

$(\overline x - E, \overline x + E)$

(840-7.844 ,  \ 840+7.844)

(832.156, \ 847.844)

4 0
3 years ago
Help me with this please! :D
Nady [450]

Answer:

#1=2

#2= 14

#3= 26

#4= 32

Step-by-step explanation:

y=6x-16

Lets use the first one as an example: since x is our variable we can plug in 3 into the equation to make y=(6x3)-16. 6x3=18, so y=18-16 which is 2. You can plug in any other number to find your answer as long as you follow the pattern in the equation.

8 0
3 years ago
Read 2 more answers
16+(18+10)=(x+18)+10
sasho [114]
16 + 18 + 10 = 44
44 = x + 28
16 = x
x = 16
4 0
2 years ago
Read 2 more answers
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