If you write .6 and .7 as fractions you get 6/10 and 7/10. If you double those you get 12/20 and 14/20, so one potential fraction between the two could be 13/20.
To get the solution, we are looking for, we need to point out what we know.
<span>1. We assume, that the number 150 is 100% - because it's the output value of the task. </span>
<span>2. We assume, that x is the value we are looking for. </span>
<span>3. If 150 is 100%, so we can write it down as 150=100%. </span>
<span>4. We know, that x is 16% of the output value, so we can write it down as x=16%. </span>
5. Now we have two simple equations:
1) 150=100%
2) x=16%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
150/x=100%/16%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.
7. Solution for what is 16% of 150
150/x=100/16
<span>(150/x)*x=(100/16)*x - </span>we multiply both sides of the equation by x
<span>150=6.25*x - </span>we divide both sides of the equation by (6.25) to get x
<span>150/6.25=x </span>
<span>24=x </span>
x=24
<span>now we have: </span>
<span>16% of 150=24</span>
I need to know the dimensions to solve. Ex: "Line AC is 2.5 centimeters"
My bad - should've asked that under "Ask For Details."
Sorry :(
Width = w
length = 11w
Pythagoras theorem
a^2 + b^2 = c^2
Let's say the width is a, the length is b, and the distance between corners (call it d) is c
w^2 + 11w^2 = d^2
Collect like terms,
12w^2 = d^2
Simply
12w = d
