Answer:
- Both are terminating decimals
Step-by-step explanation:
<u>Answer to your questions:</u>
- First of all, both A and B are correct and both quotients are terminating decimals.
- To find out if the decimal is terminating or not, multiply the quotient by divisor. If you get exactly the same number as dividend, then it is terminating otherwise it is non-terminating.
- The fraction may have greater numerator than denominator, in this case the quotient will be greater than one.
- Now regarding simplification. You would be asked to give an answer rounded to some extend. One decimal place, two decimal places, 3 significant numbers etc. For the first operation you would get 34.8 (rounded to nearest tenth).
- Or you may be asked to have a best estimated result. In this case you would round the initial numbers and find results. 205/714 ≈ 0.29
Answer:
x = 66.74715005725
Step-by-step explanation:
First you bring over the added variable. 0.194185, and subtract it from 66. Then you divide your difference by 0.985897. This gives you 66.74715005725
Well, you could assign a letter to each piece of luggage like so...
A, B, C, D, E, F, G
What you could then do is set it against a table (a configuration table to be precise) with the same letters, and repeat the process again. If the order of these pieces of luggage also has to be taken into account, you'll end up with more configurations.
My answer and workings are below...
35 arrangements without order taken into consideration, because there are 35 ways in which to select 3 objects from the 7 objects.
210 arrangements (35 x 6) when order is taken into consideration.
*There are 6 ways to configure 3 letters.
Alternative way to solve the problem...
Produce Pascal's triangle. If you want to know how many ways in which you can choose 3 objects from 7, select (7 3) in Pascal's triangle which is equal to 35. Now, there are 6 ways in which to configure 3 objects if you are concerned about order.
Answer:
x = 5
Step-by-step explanation:
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<u>FACTS TO KNOW BEFORE SOLVING</u> :-
- In an equation , if the bases are same in both L.H.S. & R.H.S. then , the power of the bases on both the sides of equation should be equal. For e.g. :
⇒
[∵ Bases are equal on both the sides]
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Lets express it in terms of 2.




Here the bases on both the sides are equal. Hence ,



The boy walks at a constant speed V=3 m/s where V is his velocity
1 minutes has 60 seconds
Thus we conclude during 1 minute he travels :
60 seconds × 3 meters/second = 180 meters