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kap26 [50]
3 years ago
12

There are 5 persons and at a time only 3 can be arranged. What is the total number of arrangements?

Mathematics
1 answer:
disa [49]3 years ago
7 0

Answer:

If there are 5 persons and at a time only 3 can be arranged, the total number of arrangements is 60

Option C is correct

Step-by-step explanation:

There are 5 persons and at a time only 3 can be arranged.

The total number of arrangements = nPr = n!/(n-r)!

Here n = 5 and r = 3

nPr = n!/(n-r)!

nPr = 5!(5-3)!

nPr = 5!/2!

nPr = 5*4*3*2!/2!

nPr = 5*4*3

nPr = 60

So, if there are 5 persons and at a time only 3 can be arranged, the total number of arrangements is 60

Option C is correct.

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Match each expression to another expression with the same value. 24 ÷ 3 53 × 7 56 − 21 4 − 3 40 × 2 8 × 50 8 × (5 × 12 − 10) (8
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Answer:

a. 24 ÷ 3  = 8                       ⇒              i. 8 × 3 ÷ (6 − 3)  = 8

b. 53 × 7 = 371                     ⇒             h. (8 × 7 − 3) × 7 = 371

g. 8 × (5 × 12 − 10) = 400    ⇒             f. 8 × 50 = 400

Step-by-step explanation:

Given:

We have to match the equivalent expressions:

a. 24 ÷ 3                 f. 8 × 50

b. 53 × 7                 g. 8 × (5 × 12 − 10)

c. 56 − 21               h. (8 × 7 − 3) × 7

d. 4 − 3                   i. 8 × 3 ÷ (6 − 3)

                e. 40 × 2          

             

Solution:

a. 24 ÷ 3 = 8                

b. 53 × 7 = 371            

c. 56 − 21 = 35            

d. 4 − 3 = 1  

e. 40 × 2 =80                            

f. 8 × 50 = 400                      

g. 8 × (5 × 12 − 10)  <em>Using PEMDAS rule.</em>

⇒ 8\times (60-10)

⇒ 8\times 50

⇒ 400

h. (8 × 7 − 3) × 7

⇒ (56-3)\times 7

⇒ (53)\times 7

⇒ 371

i. 8 × 3 ÷ (6 − 3) = 8

⇒ \frac{8\times 3}{3}

⇒ \frac{24}{3}

⇒ 8

Answers:

a. 24 ÷ 3  = 8                       ⇒              i. 8 × 3 ÷ (6 − 3)  = 8

b. 53 × 7 = 371                     ⇒             h. (8 × 7 − 3) × 7 = 371

g. 8 × (5 × 12 − 10) = 400    ⇒             f. 8 × 50 = 400

c,d and e didn't have any match    

a is equivalent to i,b equivalent to h and g is equivalent to f.

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