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Ugo [173]
3 years ago
8

Please help me before i fail!! Find the solution(s) of the following equation.

Mathematics
2 answers:
TEA [102]3 years ago
6 0

Answer: A or B but really A

Step-by-step explanation:

c² = 144/169

√c² = √144/169

c = 12/13

  or

-12/13² = 144/169

Hope that helped! I recommend choosing A

miss Akunina [59]3 years ago
6 0

Answer: A and B.

Step-by-step explanation:

When you multiply 12 by 12, you get 144, and when you multiply 13 by 13, you get 169.

This works with negatives too because a negative times a negative is a positive.

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Consider a uniform distribution from aequals4 to bequals29. ​(a) Find the probability that x lies between 7 and 27. ​(b) Find th
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Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

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Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

P(c \leq x \leq d) = \frac{d - c}{b - a}

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(a) Find the probability that x lies between 7 and 27.

So c = 7, d = 27

P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8

80% probability that x lies between 7 and 27.

​(b) Find the probability that x lies between 6 and 13. ​

So c = 6, d = 13

P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

​So c = 9, d = 20

P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So c = 11, d = 18

P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28

28% probability that x lies between 11 and 18.

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2 years ago
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Step-by-step explanation:

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