Answer:
The value of the test statistic and degrees of freedom is 2.148 and 11 respectively.
Step-by-step explanation:
Consider the provided information.
The mean annual tuition and fees for a sample of 12 private colleges was 36,800 with a standard deviation of 5,000 .
Thus, n = 12,
σ = 5000
degrees of freedom = n-1 = 12-1 = 11

Formula to find the value of z is: 
Where
is mean of sample, μ is the mean of population, σ is the standard deviation of population and n is number of observations.


Hence, the value of the test statistic and degrees of freedom is 2.148 and 11 respectively.
Fifth root of x is x^1/5 as an exponential expression. . This to the 7th power is
x ^(1/5 * 7) which is x^(7/5). Bringing this to the third power is x^ (21/5) which is your answer.
- The kind of curve obtained is linear.
- The relationship between the variables is direct variation.
- After 4.5 seconds, I expect the velocity to be equal to 140 ft/s.
- The amount of time required for the object to attain a speed of 100 ft/s is 3.2 seconds.
<h3>What is a graph?</h3>
A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a Cartesian coordinate, which are the x-axis and y-axis.
In this exercise, you're required to plot a graph for the data (velocity and time) recorded for an object that is falling from rest.
Based on the graph for the data (see attachment), we can logically deduce the following points:
- The kind of curve obtained is linear.
- The relationship between the variables is direct variation.
- After 4.5 seconds, I expect the velocity to be equal to 140 ft/s.
- The amount of time required for the object to attain a speed of 100 ft/s is 3.2 seconds.
Read more on graphs here: brainly.com/question/25875680
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Complete Question:
Plot a graph for the following data recorded for an object falling from rest
a. What kind of a curve did you obtain?
b. What is the relationship between the variables?
c. What do you expect the velocity to be after 4.5 s?
d. How much time is required for the object to attain a speed of 100 ft/s?
Answer:
Step-by-step explanation:
Since radar reports 30 tracks in one minute in which 60 seconds makes 1 minute
Let calculate using this formula
Using this formula
Percentage of time=Tracks reported in minutes/60 seconds*100
Let plug in the formula
Percentage of time=30 tracks/60 seconds*100
Percentage of time=0.5*100
Percentage of time=50%
Inconclusion The percentage of the time that radar track the aircraft is 50%
Answer:
$11, $13, $14
Step-by-step explanation:
all of those answers are greater than $9 but less than or equal to $14.