Heya !
Using a theoram about triangles ,
Given a triangle ∆ABC, the sum of the lengths of any two sides of the triangle is greater than the length of the third side ,
Also , the length of third side always greater than absolute difference of the other two sides ,
Let the third side be x ,
So , x < 9 + 8 and x > 9 - 8
x < 17 and x > 1
Hence , x ∈ [ 2 , 17 ] inch.
Above case is true for any triangle , be it scalene , Isosceles , Right-angled ...
As , for Isosceles , the third side can be 8 or 9 inches ,
For scalene , all values in the above range satusfies ,
For right angled triangle , we have 2 cases ,
Case 1 : Third side is the hypotenuse
Then , x = √(9²+8²) = √145 = 12.0415 inch.
Case 2 : Third side is not the hypotenuse
Then , x = √(9²-8²) = √17 = 4.1231 inch.
Hope it helps you ! :)
Answer:
c
Step-by-step explanation:
Answer:
The production would be 25 wheels,
Lowest average cost is $ 123.75
Step-by-step explanation:
Given cost function,

Where,
x = number of wheel,
So, the average cost per wheel,

Differentiating with respect to x,

Again differentiating with respect to x,

For maxima or minima,




For x = 25, A''(x) = positive,
i.e. A(x) is maximum at x = 25.
Hence, the production would be 25 wheels for the lowest average cost per wheel.
And, lowest average cost,
A(x) = 0.09(25)² - 4.5(25) + 180 = $ 123.75
Answer: OPTION A.
Step-by-step explanation:
Given the following function:

You know that it represents the the height of the ball (in meters) when it is a distance "x" meters away from Rowan.
Since it is a Quadratic function its graph is parabola.
So, the maximum point of the graph modeling the height of the ball is the Vertex of the parabola.
You can find the x-coordinate of the Vertex with this formula:

In this case:

Then, substituting values, you get:

Finally, substitute the value of "x" into the function in order to get the y-coordinate of the Vertex:
Therefore, you can conclude that:
<em> The maximum height of the ball is 0.75 of a meter, which occurs when it is approximately 1 meter away from Rowan.</em>