Answer:
A. Right triangle
B. Scalene triangle
C. Equilateral triangle
D. Scalene
Step-by-step explanation:
Answer:
y = 1/2 x²
Step-by-step explanation:
The coefficient of the first term in a quadratic, in our case here, x², will tell us how the graph stretches. This is akin to the slope within the linear graph. Similar to the slope, the smaller the coefficient value, or value of slope m, the shallower the angle.
When discussing quadratics, the larger the coefficient of our x² term, the steeper, and skinnier the graph. If we want to look for a graph that is wider than y = 2x², then we need to find a graph with a coefficient that is less than 2.
Our only option then is
y = 1/2 x²
Answer:
I think its 1.2
Step-by-step explanation:
Answer:
The answer to the question
This problem is a projectile problem. The initial velocity is 50m/s at an optimum angle of 45. The maximum height or the height of the y component is at it's highest is asked.
Informtion needed:
Acceleration due to gravity = 9.81m/s^2
Formula:
Hmax = ((V^2)(sin(angle))^2)/2g
Hmax = ((50^2)(sin45)^2)/(2*9.81) = 63.71 or letter B 63.5 m is the closest answer.
