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madreJ [45]
3 years ago
8

(sum by gcf ) what is the gcf of 44+40? 44+40=4 (__+__)

Mathematics
2 answers:
kati45 [8]3 years ago
6 0
44|2
22|2
11|11
1

40|2
20|2
10|2
5|5
1

GCF(40,44)=2^2=4

44+40=4\cdot11+4\cdot10=4(11+10)
Illusion [34]3 years ago
4 0


The answer is 4

|________ you put 44+40 in the box

  |_______ then you see what goes into both and it is 4 so then divide 44 and 40 by 4

then put 11+10 in the box and nothing goes into 11 and 10 so 4 is the only thing that goes into 44 +40

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A cylindrical soup can has a diameter of 3.6 in. and is 6.4 in. tall. Find the volume of the can.
arsen [322]
<h2>⚘Your Answer:------</h2>

<h3><u>Given</u><u> </u><u>Information</u><u>:</u></h3>

  • <u>Diameter of can</u>:- 3.6 cm
  • <u>Height of</u><u> </u><u>can</u><u>:</u><u>-</u> 6.4 cm

<h3><u>To</u><u> </u><u>Find</u><u> </u><u>Out</u><u>:</u></h3>

  • <u>Volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>Can</u><u>.</u>

<h3><u>Solution</u><u>:</u></h3>

Radius = (Diameter/2)

ㅤㅤㅤㅤ3.6 cm/2

ㅤㅤㅤㅤ1.8 cm

<u>So</u><u>,</u><u> </u><u>Radius</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>soup</u><u> </u><u>can</u><u> </u><u>is</u> 1.8 cm.

Volume øf cylinder = Volume øf can

Volume of cylinder = π r²h

(π = 22/7)

(r = radius = 1.8 cm)

(h = height = 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7×(1.8 cm)²× 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7× 3.24 cm² × 6.4 cm

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 22/7 × 20.736 cm³

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= (456.192/7) cm³

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ= 65.17 cm³

So, the Volume of the soup can is 65.17 cm³

ㅤㅤㅤㅤㅤㅤㅤㅤ⚘Thank You

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