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kicyunya [14]
3 years ago
11

I need help with this its a bit easy will mark brainlist

Mathematics
2 answers:
LenKa [72]3 years ago
8 0

Answer:

First box: y/x = 38/2 = 19

Second box: y/x = 57/3 = 19

Third box: y/x = 76/4 = 19

Constant of proportionality = 19

Equation: y = 19x

masha68 [24]3 years ago
5 0
Hopefully you can read it

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Help ixl sucks pleasssssssssssse
LUCKY_DIMON [66]

Answer:

11.5

Step-by-step explanation:

98.9 / 8.6 = 11.5

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3 years ago
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What is the range of the function f(x) = 2x+3
MrRissso [65]

Answer: (-∞,∞)

Step-by-step explanation: The line extends forever in both directions meaning that the endpoints will be negative infinity and infinity.

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3 years ago
7 1/2 divided by 3/4
creativ13 [48]

Answer:

10

Step-by-step explanation:

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3 years ago
If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn
mash [69]

Let a=\tan A and b=\sin A. Then

m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab

\implies m^2-n^2=4\tan A\sin A

and

mn=(a+b)(a-b)=a^2-b^2

\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}

The expression under the square root can be rewritten as

\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)

Recall that

\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A

so that

\tan^2A-\sin^2A=\sin^2A\tan^2A

and assuming \sin A>0 and \tan A>0, we end up with

4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A

so that

m^2-n^2=4\sqrt{mn}

as required.

5 0
3 years ago
Simplify -9(1-10n) - 2(3n+9)
agasfer [191]

Answer:

3 (28 n - 9)

Step-by-step explanation:

Simplify the following:

-9 (1 - 10 n) - 2 (3 n + 9)

-9 (1 - 10 n) = 90 n - 9:

90 n - 9 - 2 (3 n + 9)

-2 (3 n + 9) = -6 n - 18:

90 n + -6 n - 18 - 9

Grouping like terms, 90 n - 6 n - 18 - 9 = (90 n - 6 n) + (-9 - 18):

(90 n - 6 n) + (-9 - 18)

90 n - 6 n = 84 n:

84 n + (-9 - 18)

-9 - 18 = -27:

84 n + -27

Factor 3 out of 84 n - 27:

Answer: 3 (28 n - 9)

4 0
3 years ago
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