We can find the number of extra clubs in the deck from the given probability, since the probability of drawing a diamond and a club is
but this would imply that
, which suggests we're taking 4 clubs out of the original deck and contradicts the problem statement that there are "too many clubs".
Perhaps the question is providing the probability of drawing a diamond, THEN a club, or vice versa. In that case, we have
and solving gives
, which makes more sense. Then the number of extra spades in the deck must be 2.
For numbers 9 and 10, we are dealing with negative exponents.
The rule of exponents states that any quantity b, taken to the power -n, equals the reciprocal of b, taken to the nth power.
Example: x⁻³ = 1 / x³
Number 9: ( 3 / y² ) ⁻³
Step 1: take the reciprocal:
( 3 / y² ) ⁻³ = ( y² / 3 ) ³
Step 2: distribute the exponent
( y² / 3 ) ³ = y⁶ / 27
Try to do number 10 on your own. If you have any questions, comment.
Answer:
You could write -5.16 as -5 4/25
452.16 = 3.1416 r^2
r^2 = 452.16 / 3.1416
r^2 = 143.93
r = 11.997
C = 2 (3.1416) (12) =75.38 m
9514 1404 393
Answer:
375 hamburgers
Step-by-step explanation:
Let h represent the number of hamburgers. Then h+63 is the number of cheeseburgers, and the combined total is ...
h +(h +63) = 813
2h = 813 -63 = 750
h = 750/2 = 375
375 hamburgers were sold on Saturday.
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<em>Additional comment</em>
In a "sum and difference" problem like this, the smaller number is half the difference between the sum and the difference. h = (813 -63)/2 = 375. This generic solution applies to all "sum and difference" problems.
