So to solve this problem, we must convert units and then cancel units simultaneously:

Therefore we know that the distance that light travels in one year is
inches.
Explanation:
Given:
v₀ = 0 m/s
v = 49 m/s
a = 9.8 m/s²
Find: t
v = at + v₀
49 m/s = (9.8 m/s²) t + 0 m/s
t = 5 s
Solution :
A) Electric current is the flow of electrons .
B) We know, by ohm's law :
V = I × R
Putting given values in above equation, we get :
V = 0.56 × 72 V
V = 40.32 V
Hence, this is the required solution.
Answer:
a) The wavelength of light is 6×10^-7 m.
b) The size of the central peak is 6×10^-3 m.
Explanation:
let:
α be the distance between the 1st and 2nd maxima
d = 0.4 mm be the grating slit space
X be the distance to the screen
a) α = λ×X/d
λ = α×d/X
= (0.3×10^-2)×(0.4×10^-3)/(2)
= 6×10^-7 m
Therefore, the wavelength of light is 6×10^-7 m.
b) the size of the central peak is given by:
D = 2×λ×X/d
= 2×(6×10^-7)×(2)/(0.4×10^-3)
= 6×10^-3 m
Therefore, the size of the central peak is 6×10^-3 m.
Answer:
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Explanation:
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