Answer:
Magnitude of electric field = E = q/Aε0
Explanation:
Consider plates are placed at a distance of d. As given in the question the charge stored on the plates have magnitude q and given by:
q = CV
And
V = q/C ……. (i)
The capacitance is given by the following equation:
C = Aε0/d ……. (ii)
Put equation (ii) in (i)
,
V = qd/ Aε0 …..(iii)
The electric field is defined as:
E = V/d …… (iv)
Put equation (iii) in (iv),
E = qd/ Aε0d
E = q/Aε0
Hence, the magnitude of electric field will be q/Aε0 .
Answer:
10 kg
Explanation:
p=ma
25=2.5m
m=25/2.5
m=10 kg
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Answer:
20.3N
Explanation:
Given parameters:
Area of the eardrum = 0.0002m²
Pressure on the eardrum = 1atm = 101325Nm⁻²
Unknown:
Force exerted on the eardrum = ?
Solution:
Pressure is the force per unit area impacted on a body.
Pressure = 
Force = Pressure x area
Now insert the parameters and solve;
Force = 101325Nm⁻² x 0.0002m² = 20.3N
F)
size , texture , and color hope this helps
