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alex41 [277]
3 years ago
8

——PLEASE HELP QUESTION IS IN THE PIC—

Mathematics
1 answer:
kicyunya [14]3 years ago
7 0

Answer:

d. 4/5

Step-by-step explanation:

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PLEASE HELP.
solniwko [45]

recall that the radius is the distance from the center of a circle to any point on the circle.

we know the center is at -16,-14, and we know that -8,-8 is a point on the circle, so the distance between both must be the radius.


\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-16}~,~\stackrel{y_1}{-14})\qquad
(\stackrel{x_2}{-8}~,~\stackrel{y_2}{-8})\qquad \qquad
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{radius}{r}=\sqrt{[-8-(-16)]^2+[-8-(-14)]^2}
\\\\\\
r=\sqrt{(-8+16)^2+(-8+14)^2}\implies r=\sqrt{8^2+6^2}
\\\\\\
r=\sqrt{100}\implies \boxed{r=10}
\\\\[-0.35em]
\rule{34em}{0.25pt}


\bf \textit{equation of a circle}\\\\
(x- h)^2+(y- k)^2= r^2
\qquad
center~~(\stackrel{-16}{ h},\stackrel{-14}{ k})\qquad \qquad
radius=\stackrel{10}{ r}
\\\\\\\
[x-(-16)]^2+[y-(-14)]^2=10^2\implies \blacktriangleright (x+16)^2+(y+14)^2=100 \blacktriangleleft

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