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suter [353]
3 years ago
11

Describe the transformation from the graph of f(x) =ax^2 to the graph of g(x) = a(x-h)^2+k

Mathematics
1 answer:
MrRa [10]3 years ago
8 0

Answer: Step-by-step explanation:

f(x)=ax^2→g(x)=a(x-h)^2+k

The horizontal shift depends on the value of h. The horizontal shift is described as:  

g(x)=f(x+h) - The graph is shifted to the left h units.

g(x)=f(x−h) - The graph is shifted to the right h units.

Hence, in the question above, Horizontal Shift: Right h Units

The vertical shift depends on the value of k. The vertical shift is described as:

g(x)=f(x)+k - The graph is shifted up k units.

g(x)=f(x)−k - The graph is shifted down k units.

Therefore, in the question above, Vertical Shift: Up k Units

 

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Answer:

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3 years ago
Are these two expressions equivalent 4x² + 2y + 3 and 2x² + 2x + y + y + 3 yes or no​
algol13

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Step-by-step explanation:

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3 years ago
Consider angle θ in Quadrant ll, where cos θ= -12/13. what's the value of sin θ​
Bas_tet [7]

Answer:

sinθ = 5/13

Step-by-step explanation:

cosθ​ = adjacent/hypotenuse (or you could think of it as x/r)

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opposite = ?

To get the opposite, we use the Pythagorean theorem

hypotenuse^{2} = adjacent^{2}  + opposite^2

hypotenuse^{2} - adjacent^{2}  = opposite^2

\sqrt(hypotenuse^{2} - adjacent^{2})  = opposite

Now sub in the numbers:

\sqrt{(13^2 - (-12)^2)} = opposite

opposite = 5

Now sinθ = opposite/hypotenuse

so sinθ = 5/13

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